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sandm
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Hi, could someone help me please with these?
Problem 1) solve the system equations: dx/dt=4x+3y dy/dt=x+t with x(0)=2, y(0)=1 as initial conditions.
Problem 2) Find the surface area of that portion of the surface z=1 rootsquare of x^2+y^2 that lies in the first octant.
Thanks in advance.
 one year ago
 one year ago
sandm Group Title
Hi, could someone help me please with these? Problem 1) solve the system equations: dx/dt=4x+3y dy/dt=x+t with x(0)=2, y(0)=1 as initial conditions. Problem 2) Find the surface area of that portion of the surface z=1 rootsquare of x^2+y^2 that lies in the first octant. Thanks in advance.
 one year ago
 one year ago

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sashankvilla Group TitleBest ResponseYou've already chosen the best response.0
1)try to integrate the two equations
 one year ago

captainZero Group TitleBest ResponseYou've already chosen the best response.0
p.1: from equation 1, we get x''=4x'+3y', substituting y'=x+t, the problem is now a differential equation: x''4x'+3x=3t with i.c. x(0)=2, x'(0)=5. if you've done 18.03, you can solve it easily. p.2: area of the portion is \[\iint_{S}dS=\iint_{R_xy}\sqrt{(z'_x)^2+(z'_y)^2+1}dxdy\]. S is lying over area Rxy.
 10 months ago
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