A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
Hi, could someone help me please with these?
Problem 1) solve the system equations: dx/dt=4x+3y dy/dt=x+t with x(0)=2, y(0)=1 as initial conditions.
Problem 2) Find the surface area of that portion of the surface z=1 rootsquare of x^2+y^2 that lies in the first octant.
Thanks in advance.
 one year ago
Hi, could someone help me please with these? Problem 1) solve the system equations: dx/dt=4x+3y dy/dt=x+t with x(0)=2, y(0)=1 as initial conditions. Problem 2) Find the surface area of that portion of the surface z=1 rootsquare of x^2+y^2 that lies in the first octant. Thanks in advance.

This Question is Closed

sashankvilla
 one year ago
Best ResponseYou've already chosen the best response.01)try to integrate the two equations

captainZero
 one year ago
Best ResponseYou've already chosen the best response.0p.1: from equation 1, we get x''=4x'+3y', substituting y'=x+t, the problem is now a differential equation: x''4x'+3x=3t with i.c. x(0)=2, x'(0)=5. if you've done 18.03, you can solve it easily. p.2: area of the portion is \[\iint_{S}dS=\iint_{R_xy}\sqrt{(z'_x)^2+(z'_y)^2+1}dxdy\]. S is lying over area Rxy.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.