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Hi, could someone help me please with these?
Problem 1) solve the system equations: dx/dt=4x+3y dy/dt=x+t with x(0)=2, y(0)=1 as initial conditions.
Problem 2) Find the surface area of that portion of the surface z=1 rootsquare of x^2+y^2 that lies in the first octant.
Thanks in advance.
 5 months ago
 5 months ago
Hi, could someone help me please with these? Problem 1) solve the system equations: dx/dt=4x+3y dy/dt=x+t with x(0)=2, y(0)=1 as initial conditions. Problem 2) Find the surface area of that portion of the surface z=1 rootsquare of x^2+y^2 that lies in the first octant. Thanks in advance.
 5 months ago
 5 months ago

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sashankvillaBest ResponseYou've already chosen the best response.0
1)try to integrate the two equations
 5 months ago

captainZeroBest ResponseYou've already chosen the best response.0
p.1: from equation 1, we get x''=4x'+3y', substituting y'=x+t, the problem is now a differential equation: x''4x'+3x=3t with i.c. x(0)=2, x'(0)=5. if you've done 18.03, you can solve it easily. p.2: area of the portion is \[\iint_{S}dS=\iint_{R_xy}\sqrt{(z'_x)^2+(z'_y)^2+1}dxdy\]. S is lying over area Rxy.
 4 months ago
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