I have done this problem many times and it is still wrong. I know where it's wrong, at least, but do not know the answer. I look here for some different guidance from what I have been getting, hoping it will help.
( x^(2/3) / 4y(-2) ) ^(1/2)
x^(2/3)(1/2) = x^(2/6) = x^(1/3)
4^(1/2) = 2
And this is allegedly where I am making a mistake:
y^-2 * 1/2 = y^(-2/2) = y^-1 = 1/y
So for my final answer I have
x^(1/3)
-------
2/y
But this is wrong, I guess. Any help is appreciated!

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Is it 4(y)^-2 or (4y)^-2

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