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RoseDryer
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\[\frac{ q3 }{ 5 } \times \frac{ 3q }{ q4 }\]

alec.mccarty
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do the top and bottom seperatly first so
(q3)3q=
and 5(q4)=

RoseDryer
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3q^26q
and
5q+20

Easyaspi314
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3q^2  9q for the numerator

alec.mccarty
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\[\frac{ 3q^29q }{ 5+20 }\]

alec.mccarty
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5q***

RoseDryer
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Duh. Lol. I'm just tired.

RoseDryer
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Now how do I find the restrictions?

RoseDryer
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Well the excluded values?

alec.mccarty
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set then bottom = to 0 and any values you get are restricted bc you can not divide by 0

RoseDryer
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I think it's \[q \neq5\]

alec.mccarty
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4 bc 4*5=20 and 2020=0

RoseDryer
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Yeah sorry. I forgot the +20 on the bottom.

alec.mccarty
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glad to help