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RoseDryer

  • 2 years ago

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  1. RoseDryer
    • 2 years ago
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    \[\frac{ q-3 }{ -5 } \times \frac{ 3q }{ q-4 }\]

  2. alec.mccarty
    • 2 years ago
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    do the top and bottom seperatly first so (q-3)3q= and -5(q-4)=

  3. RoseDryer
    • 2 years ago
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    3q^2-6q and -5q+20

  4. Easyaspi314
    • 2 years ago
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    3q^2 - 9q for the numerator

  5. alec.mccarty
    • 2 years ago
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    \[\frac{ 3q^2-9q }{ -5+20 }\]

  6. alec.mccarty
    • 2 years ago
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    -5q***

  7. RoseDryer
    • 2 years ago
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    Duh. Lol. I'm just tired.

  8. RoseDryer
    • 2 years ago
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    Now how do I find the restrictions?

  9. RoseDryer
    • 2 years ago
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    Well the excluded values?

  10. alec.mccarty
    • 2 years ago
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    set then bottom = to 0 and any values you get are restricted bc you can not divide by 0

  11. RoseDryer
    • 2 years ago
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    I think it's \[q \neq5\]

  12. alec.mccarty
    • 2 years ago
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    4 bc 4*5=20 and 20-20=0

  13. RoseDryer
    • 2 years ago
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    Yeah sorry. I forgot the +20 on the bottom.

  14. alec.mccarty
    • 2 years ago
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    glad to help

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