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\[\frac{ q-3 }{ -5 } \times \frac{ 3q }{ q-4 }\]

do the top and bottom seperatly first so
(q-3)3q=
and -5(q-4)=

3q^2-6q
and
-5q+20

3q^2 - 9q for the numerator

\[\frac{ 3q^2-9q }{ -5+20 }\]

-5q***

Duh. Lol. I'm just tired.

Now how do I find the restrictions?

Well the excluded values?

set then bottom = to 0 and any values you get are restricted bc you can not divide by 0

I think it's \[q \neq5\]

4 bc 4*5=20 and 20-20=0

Yeah sorry. I forgot the +20 on the bottom.

glad to help