osanseviero
  • osanseviero
In a geometric series, a2=6 a5=48 Which is the first term, which is the constant and write the progression
Mathematics
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SOLVED
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chestercat
  • chestercat
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osanseviero
  • osanseviero
I know that \[an=a1*r ^{n-1}\] What goes next?
osanseviero
  • osanseviero
6=a1*r^(n-1) ?
osanseviero
  • osanseviero
6=a1*r^(2-1), 6=a1*r

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More answers

anonymous
  • anonymous
As you said : \[a_n=a_1\times q^{n-1}\] where q is the constant of the serie, so we have : \[a_2=a_1\times q\\a_5=a_1\times q^4\] Is that true ?
osanseviero
  • osanseviero
Yep
anonymous
  • anonymous
so we get : \[6=a_1\times q~~~~~~(1)\\48=a_1\times q^4~~~(2)\] Now, we can divide the equation (2) over (1) , what should we get ?
osanseviero
  • osanseviero
8=q^3, q=2!
anonymous
  • anonymous
Good. Now the 1st term can be found easily, can't it ?
osanseviero
  • osanseviero
yepp :D
osanseviero
  • osanseviero
3 :) thanks
osanseviero
  • osanseviero
So an=3*2^n-1 ?
anonymous
  • anonymous
Yes, it is ! And you are welcome !

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