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In a geometric series,
a2=6
a5=48
Which is the first term, which is the constant and write the progression
 5 months ago
 5 months ago
In a geometric series, a2=6 a5=48 Which is the first term, which is the constant and write the progression
 5 months ago
 5 months ago

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osansevieroBest ResponseYou've already chosen the best response.0
I know that \[an=a1*r ^{n1}\] What goes next?
 5 months ago

osansevieroBest ResponseYou've already chosen the best response.0
6=a1*r^(21), 6=a1*r
 5 months ago

Noura11Best ResponseYou've already chosen the best response.2
As you said : \[a_n=a_1\times q^{n1}\] where q is the constant of the serie, so we have : \[a_2=a_1\times q\\a_5=a_1\times q^4\] Is that true ?
 5 months ago

Noura11Best ResponseYou've already chosen the best response.2
so we get : \[6=a_1\times q~~~~~~(1)\\48=a_1\times q^4~~~(2)\] Now, we can divide the equation (2) over (1) , what should we get ?
 5 months ago

Noura11Best ResponseYou've already chosen the best response.2
Good. Now the 1st term can be found easily, can't it ?
 5 months ago

Noura11Best ResponseYou've already chosen the best response.2
Yes, it is ! And you are welcome !
 5 months ago
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