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osanseviero
 3 years ago
In a geometric series,
a2=6
a5=48
Which is the first term, which is the constant and write the progression
osanseviero
 3 years ago
In a geometric series, a2=6 a5=48 Which is the first term, which is the constant and write the progression

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osanseviero
 3 years ago
Best ResponseYou've already chosen the best response.0I know that \[an=a1*r ^{n1}\] What goes next?

osanseviero
 3 years ago
Best ResponseYou've already chosen the best response.06=a1*r^(21), 6=a1*r

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0As you said : \[a_n=a_1\times q^{n1}\] where q is the constant of the serie, so we have : \[a_2=a_1\times q\\a_5=a_1\times q^4\] Is that true ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so we get : \[6=a_1\times q~~~~~~(1)\\48=a_1\times q^4~~~(2)\] Now, we can divide the equation (2) over (1) , what should we get ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Good. Now the 1st term can be found easily, can't it ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, it is ! And you are welcome !
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