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osanseviero
Group Title
In a geometric series,
a2=6
a5=48
Which is the first term, which is the constant and write the progression
 10 months ago
 10 months ago
osanseviero Group Title
In a geometric series, a2=6 a5=48 Which is the first term, which is the constant and write the progression
 10 months ago
 10 months ago

This Question is Closed

osanseviero Group TitleBest ResponseYou've already chosen the best response.0
I know that \[an=a1*r ^{n1}\] What goes next?
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.0
6=a1*r^(n1) ?
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.0
6=a1*r^(21), 6=a1*r
 10 months ago

Noura11 Group TitleBest ResponseYou've already chosen the best response.2
As you said : \[a_n=a_1\times q^{n1}\] where q is the constant of the serie, so we have : \[a_2=a_1\times q\\a_5=a_1\times q^4\] Is that true ?
 10 months ago

Noura11 Group TitleBest ResponseYou've already chosen the best response.2
so we get : \[6=a_1\times q~~~~~~(1)\\48=a_1\times q^4~~~(2)\] Now, we can divide the equation (2) over (1) , what should we get ?
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.0
8=q^3, q=2!
 10 months ago

Noura11 Group TitleBest ResponseYou've already chosen the best response.2
Good. Now the 1st term can be found easily, can't it ?
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.0
yepp :D
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.0
3 :) thanks
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.0
So an=3*2^n1 ?
 10 months ago

Noura11 Group TitleBest ResponseYou've already chosen the best response.2
Yes, it is ! And you are welcome !
 10 months ago
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