A community for students.
Here's the question you clicked on:
 0 viewing
osanseviero
 one year ago
In a geometric series,
a2=6
a5=48
Which is the first term, which is the constant and write the progression
osanseviero
 one year ago
In a geometric series, a2=6 a5=48 Which is the first term, which is the constant and write the progression

This Question is Closed

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.0I know that \[an=a1*r ^{n1}\] What goes next?

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.06=a1*r^(21), 6=a1*r

Noura11
 one year ago
Best ResponseYou've already chosen the best response.2As you said : \[a_n=a_1\times q^{n1}\] where q is the constant of the serie, so we have : \[a_2=a_1\times q\\a_5=a_1\times q^4\] Is that true ?

Noura11
 one year ago
Best ResponseYou've already chosen the best response.2so we get : \[6=a_1\times q~~~~~~(1)\\48=a_1\times q^4~~~(2)\] Now, we can divide the equation (2) over (1) , what should we get ?

Noura11
 one year ago
Best ResponseYou've already chosen the best response.2Good. Now the 1st term can be found easily, can't it ?

Noura11
 one year ago
Best ResponseYou've already chosen the best response.2Yes, it is ! And you are welcome !
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.