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osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Infinite? and how to demostrate it?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1which progression is the sequence in ?

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1The question: 1. Determine if the next sequence has a limit (demostrate it) and determine it (hint:find the general term) c) 1,1 + 2,1 + 2 + 3,1 + 2 + 3, + 4...

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1I cant find any order...

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1each term is just the sum of '1st n natural numbers'

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1thats your general term \(a_n =n(n+1)/2\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1how do you find whether next sequence has a limit ?

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Why is that the general term?

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1a1=1(1+1)/2=2/2=1 Does not apply...

hartnn
 one year ago
Best ResponseYou've already chosen the best response.11st term is indeed 1 right ? 1, 1+2 , 1+2+3 , .... 1,3,6, 10,...

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1and each term is sum of 1st n natural numbers 1st term = 1 2nd term = sum of 1st 2 natural numbers =1+2 =3 and so on

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Oh...now I understand! Give me a minute

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Cant you add the series plus iteslf? like this: Sn= 1 + 3 + 6 + 10 + ... + n2 + n1 + n Sn= n + n1 + n2 +...+ 6 + 3 + 1

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1So: 2Sn= (n+1) + (n+2) + (n+4)...ehm...this is not going right

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so you want to find the sum ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(\Large (1/2)\sum (n^2+n) = (1/2)\sum n^2+(1/2)\sum n=...?\)

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Oh...I thought that I could add Sn + Sn, and then divide them by two to get the general term

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1possible but i don't think its that easy....

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1then how to get the limit?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1how do you find whether next sequence has a limit ? i may know it, but not in these "limit of next sequence" terms ...

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1When it says "the next sequence" it refers to the one I put

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1ok, so you just want to find whether the sum converges or not ?

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Look, I have 5 exercises 1. \[\left( 1 \right)^{n}\left( \frac{ 5n+4 }{ 2n } \right)\] For this one we saw that the 4 will be nothing in comparison so the limit without the 1n is 5/2. It has no limit because it is ocilating. 2. \[2^{1}\times2^{2}\times2^{3}...\] Because there is a negative sign, it will change, so there is no limit

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1What means converges?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1sum converge means sum = finite

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1I want to know if it has a limit and to demostrate and determine it. I think that for this infinite is the limit, am I right?

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1How did you wrote the general term? Is there a mathematical way to get it?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1the sum of 1st n natural numbers ? that you can find by your method, Sn = 1+2+3+....n Sn = n+n1 +n2 +...3+2+1 2Sn = (1+n)+ (1+n) +..... so, each pair sum is (1+n) and there are n terms so, 2Sn = n (n+1)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so, sum of 1st n natural numbers = n (n+1)/2

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1that became your general term and for your sequence, you need to sum this, and whne n becomes large the sum goes on increaseing which menas this progression has no limit.

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1\[an?\left\{ an=\frac{ 1 }{ 2 }\left( a _{n1} + \frac{ 10 }{ a _{n1} }\right) \right\} for n \ge2\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1have you solved such problems, with a (n1) , before.... because i just could think of finding, a1,a2,a3...and see whether there's any pattern...

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1but I dont have a1

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1this is just telling you that the new value is the last one added by 10 divded by iteslf \[\left( a ^{2} +\frac{ 10 }{ a ^{2} }\right)\] divided by two

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yes, i though it was already given....

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1So can it be determined with the things given?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1i am not sure about this....can you ask in new post so that others can try.....sorry.
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