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amonaroll32 Group Title

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  • 10 months ago
  • 10 months ago

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  1. amonaroll32 Group Title
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    A real number x is chosen at random such that -2<=x<=5. What is the probability that x^2<2?

    • 10 months ago
  2. hwtrain Group Title
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    Do you mean?\[-2\le x \le5\]

    • 10 months ago
  3. amonaroll32 Group Title
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    Yeah @hwtrain

    • 10 months ago
  4. zimmah Group Title
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    Assuming each of the values has equal probability of occurring, you can have any value including and between -2 and 5 equally likely. Which of these numbers when squared will result in a value smaller than 2?

    • 10 months ago
  5. zimmah Group Title
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    Since it's a suffienctly small sample you can just try them each if you are not sure if they are smaller than 2 when squared

    • 10 months ago
  6. amonaroll32 Group Title
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    @zimmah There is an infinite number (decimals count)

    • 10 months ago
  7. zimmah Group Title
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    My bad.

    • 10 months ago
  8. zimmah Group Title
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    Then, a slightly different approach is needed

    • 10 months ago
  9. zimmah Group Title
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    Since the number squared has to be smaller than 2, the number itself must be smaller than the root of two, but since it's squared also negative numbers will result in positive so every value between -sqrt2 and +sqrt2 would do

    • 10 months ago
  10. amonaroll32 Group Title
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    So would it be 2(sqrt2) over 7?

    • 10 months ago
  11. zimmah Group Title
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    Then, you should probably get the ratio of -sqrt2 to -2 to see how much chance you have forthwith neat tsing of the line, and the same for the positive side.

    • 10 months ago
  12. zimmah Group Title
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    I guess so. I'm not 100% certain but sounds about riht

    • 10 months ago
  13. amonaroll32 Group Title
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    Thanks!

    • 10 months ago
  14. zimmah Group Title
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    Sorry for my spelling but theis website has horror input lag on ipad and also autocorrect from ipad tesla :s

    • 10 months ago
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