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amonaroll32

  • one year ago

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  1. amonaroll32
    • one year ago
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    A real number x is chosen at random such that -2<=x<=5. What is the probability that x^2<2?

  2. hwtrain
    • one year ago
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    Do you mean?\[-2\le x \le5\]

  3. amonaroll32
    • one year ago
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    Yeah @hwtrain

  4. zimmah
    • one year ago
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    Assuming each of the values has equal probability of occurring, you can have any value including and between -2 and 5 equally likely. Which of these numbers when squared will result in a value smaller than 2?

  5. zimmah
    • one year ago
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    Since it's a suffienctly small sample you can just try them each if you are not sure if they are smaller than 2 when squared

  6. amonaroll32
    • one year ago
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    @zimmah There is an infinite number (decimals count)

  7. zimmah
    • one year ago
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    My bad.

  8. zimmah
    • one year ago
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    Then, a slightly different approach is needed

  9. zimmah
    • one year ago
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    Since the number squared has to be smaller than 2, the number itself must be smaller than the root of two, but since it's squared also negative numbers will result in positive so every value between -sqrt2 and +sqrt2 would do

  10. amonaroll32
    • one year ago
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    So would it be 2(sqrt2) over 7?

  11. zimmah
    • one year ago
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    Then, you should probably get the ratio of -sqrt2 to -2 to see how much chance you have forthwith neat tsing of the line, and the same for the positive side.

  12. zimmah
    • one year ago
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    I guess so. I'm not 100% certain but sounds about riht

  13. amonaroll32
    • one year ago
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    Thanks!

  14. zimmah
    • one year ago
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    Sorry for my spelling but theis website has horror input lag on ipad and also autocorrect from ipad tesla :s

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