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osanseviero

  • one year ago

In a group, the 80% is married. 75% of the married have a work. 5% does not have a work and are not marrid

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  1. osanseviero
    • one year ago
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    What percentage does not have a work?

  2. osanseviero
    • one year ago
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    25% I think

  3. osanseviero
    • one year ago
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    |dw:1383266857976:dw| Is that right?

  4. osanseviero
    • one year ago
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    The last 25% is without

  5. HawkCrimson
    • one year ago
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    actually i got a different answer, we know this much 80% = married 75 % = married and work 5% = married and do not work from this we know that out of the 80% of the people, only 5% do not have a job. so now let look at the remaining 20% of non married people

  6. HawkCrimson
    • one year ago
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    we know this much 5% = people who arent married and do not work so far this is all be know from the info provided but the question doesnt mention anything about the remaining 15% but, we can reason out that the 15% much be people who are not married but work there fore 15% = not married but work

  7. HawkCrimson
    • one year ago
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    finally, out of the 80% of married people, only 5% do not have jobs and out of the 20% of single people only 5% do not have job. to conclude, there are a total of 10% of people that do not have jobs, 10% is ur answer

  8. HawkCrimson
    • one year ago
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    i am sorry that it was so long but i hope that you understood it, any questions?

  9. osanseviero
    • one year ago
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    But the problem says Married: 80% (of the total) With work: 75% (of the married, so this is 75% of 80, so it would be a 60% of the total) Without a work: 5% (of the total, so itwould be 25% of a 20%) Single: 20%

  10. osanseviero
    • one year ago
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    I am right until there?

  11. HawkCrimson
    • one year ago
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    |dw:1383269057108:dw|

  12. osanseviero
    • one year ago
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    Ok, perfect, so a 10% has no work

  13. osanseviero
    • one year ago
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    wait

  14. osanseviero
    • one year ago
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    But the 75% apply to the married people, so it is 75% of 80%, (60)

  15. osanseviero
    • one year ago
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    |dw:1383269250683:dw|

  16. HawkCrimson
    • one year ago
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    ok and the 5% does not have a work and are not marrid, is that 5% of 100%? or something else?

  17. HawkCrimson
    • one year ago
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    the quesiton doesnt specify if that 5% is of the 100% or the remaining 20%

  18. osanseviero
    • one year ago
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    "Finally, 5% are not married and neither have a work" I think it is of the 100%

  19. HawkCrimson
    • one year ago
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    i agree with you that it's 75% of 80%, ill change that now, but before i do, i would think 5% of 100% as well

  20. HawkCrimson
    • one year ago
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    yea i think it's 25% as well, sry for mis reading the question

  21. HawkCrimson
    • one year ago
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    but atleast u got a 2nd opinion in the end!

  22. osanseviero
    • one year ago
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    Hahaha thanks :)

  23. osanseviero
    • one year ago
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    The hard question is: if one person has a work, which is the probability of him being married

  24. osanseviero
    • one year ago
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    \[P(A\B) = \frac{ P(A intersecting with B)}{ B }\]

  25. osanseviero
    • one year ago
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    Is that useful for this one?

  26. HawkCrimson
    • one year ago
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    im not familiar with that equation, but ik you dont need it, it can be reasoned out

  27. osanseviero
    • one year ago
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    P(A)=3/4 (probability of being married P(B)= 3/4 (probability of having a job)

  28. osanseviero
    • one year ago
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    Mmm...75% of the 75%

  29. osanseviero
    • one year ago
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    or 75% of 60%

  30. HawkCrimson
    • one year ago
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    im a calc student so idk statistic equations lol but ik that i can reason it out lol 1 sec

  31. HawkCrimson
    • one year ago
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    id say 60% are married and work, 15% arnt married but work. there fore we find 60/75 x 100 and that should give us our answer

  32. HawkCrimson
    • one year ago
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    i got 80%

  33. HawkCrimson
    • one year ago
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    wait

  34. osanseviero
    • one year ago
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    Ok

  35. HawkCrimson
    • one year ago
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    yep i got 80%

  36. osanseviero
    • one year ago
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    Can you explain me again the logic? You want to calculate the 75% of the 60%, but why?

  37. HawkCrimson
    • one year ago
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    kk, i did it in a calculus way though xD but u seem smart enough to understadn it :) Let x = total number of people y = 75% of x (number of people working) and let z = 60% of x (number of people married and working) therefore z/y times 100 = the percentage of married and working compared to just working)

  38. HawkCrimson
    • one year ago
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    therefore z/y of 100 = 60% of x / 75% of x times 100 the x cancels so 60/100 / 75/100 times 100 60/75 times 100

  39. HawkCrimson
    • one year ago
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    if that makes sense xD

  40. HawkCrimson
    • one year ago
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    does that make any sense?

  41. osanseviero
    • one year ago
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    Yes :D thanks

  42. osanseviero
    • one year ago
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    The last question is what percentage is married inside the ones that does not have a job

  43. osanseviero
    • one year ago
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    So... 75-100 x-80 Can that apply? 80*75 divded by 100

  44. osanseviero
    • one year ago
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    I mean x-25

  45. osanseviero
    • one year ago
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    Let me formulate that again

  46. osanseviero
    • one year ago
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    x=total y=75% of x z=25% of x

  47. osanseviero
    • one year ago
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    75/25=3*

  48. HawkCrimson
    • one year ago
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    in this case x = total y = 25% of x (people with no jobs) z = 20% of x (people who are married and do not have a job) z/y times 100 = 20/25 times 100 = 80%.. wait, again? O.o

  49. HawkCrimson
    • one year ago
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    i dont see anything wrong with it, wat do you think? looks right to me

  50. osanseviero
    • one year ago
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    Looks good o.O

  51. HawkCrimson
    • one year ago
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    lol it's just fishy but yea xD

  52. osanseviero
    • one year ago
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    Do you want with another question? :) (similar problem)

  53. osanseviero
    • one year ago
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    Btw, thanks a lot

  54. HawkCrimson
    • one year ago
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    yea sure, how many questions do you have to do?

  55. osanseviero
    • one year ago
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    One problem more :) but it has 4 questions

  56. HawkCrimson
    • one year ago
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    btw, do you have to show working? cause i can bet ur teacher would of wanted you to of solved it a different way xD

  57. HawkCrimson
    • one year ago
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    but sure, u can post the last question as a new topic

  58. osanseviero
    • one year ago
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    Probably he wanted...but he is happy if he sees us having any way. He likes us to be independent. I will post next one

  59. HawkCrimson
    • one year ago
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    kk, but still id be nice to learn another way cause this way is tedious. probably there is an equation that would of made all of this simple

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