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In a group, the 80% is married. 75% of the married have a work. 5% does not have a work and are not marrid

Mathematics
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What percentage does not have a work?
25% I think
|dw:1383266857976:dw| Is that right?

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Other answers:

The last 25% is without
actually i got a different answer, we know this much 80% = married 75 % = married and work 5% = married and do not work from this we know that out of the 80% of the people, only 5% do not have a job. so now let look at the remaining 20% of non married people
we know this much 5% = people who arent married and do not work so far this is all be know from the info provided but the question doesnt mention anything about the remaining 15% but, we can reason out that the 15% much be people who are not married but work there fore 15% = not married but work
finally, out of the 80% of married people, only 5% do not have jobs and out of the 20% of single people only 5% do not have job. to conclude, there are a total of 10% of people that do not have jobs, 10% is ur answer
i am sorry that it was so long but i hope that you understood it, any questions?
But the problem says Married: 80% (of the total) With work: 75% (of the married, so this is 75% of 80, so it would be a 60% of the total) Without a work: 5% (of the total, so itwould be 25% of a 20%) Single: 20%
I am right until there?
|dw:1383269057108:dw|
Ok, perfect, so a 10% has no work
wait
But the 75% apply to the married people, so it is 75% of 80%, (60)
|dw:1383269250683:dw|
ok and the 5% does not have a work and are not marrid, is that 5% of 100%? or something else?
the quesiton doesnt specify if that 5% is of the 100% or the remaining 20%
"Finally, 5% are not married and neither have a work" I think it is of the 100%
i agree with you that it's 75% of 80%, ill change that now, but before i do, i would think 5% of 100% as well
yea i think it's 25% as well, sry for mis reading the question
but atleast u got a 2nd opinion in the end!
Hahaha thanks :)
The hard question is: if one person has a work, which is the probability of him being married
\[P(A\B) = \frac{ P(A intersecting with B)}{ B }\]
Is that useful for this one?
im not familiar with that equation, but ik you dont need it, it can be reasoned out
P(A)=3/4 (probability of being married P(B)= 3/4 (probability of having a job)
Mmm...75% of the 75%
or 75% of 60%
im a calc student so idk statistic equations lol but ik that i can reason it out lol 1 sec
id say 60% are married and work, 15% arnt married but work. there fore we find 60/75 x 100 and that should give us our answer
i got 80%
wait
Ok
yep i got 80%
Can you explain me again the logic? You want to calculate the 75% of the 60%, but why?
kk, i did it in a calculus way though xD but u seem smart enough to understadn it :) Let x = total number of people y = 75% of x (number of people working) and let z = 60% of x (number of people married and working) therefore z/y times 100 = the percentage of married and working compared to just working)
therefore z/y of 100 = 60% of x / 75% of x times 100 the x cancels so 60/100 / 75/100 times 100 60/75 times 100
if that makes sense xD
does that make any sense?
Yes :D thanks
The last question is what percentage is married inside the ones that does not have a job
So... 75-100 x-80 Can that apply? 80*75 divded by 100
I mean x-25
Let me formulate that again
x=total y=75% of x z=25% of x
75/25=3*
in this case x = total y = 25% of x (people with no jobs) z = 20% of x (people who are married and do not have a job) z/y times 100 = 20/25 times 100 = 80%.. wait, again? O.o
i dont see anything wrong with it, wat do you think? looks right to me
Looks good o.O
lol it's just fishy but yea xD
Do you want with another question? :) (similar problem)
Btw, thanks a lot
yea sure, how many questions do you have to do?
One problem more :) but it has 4 questions
btw, do you have to show working? cause i can bet ur teacher would of wanted you to of solved it a different way xD
but sure, u can post the last question as a new topic
Probably he wanted...but he is happy if he sees us having any way. He likes us to be independent. I will post next one
kk, but still id be nice to learn another way cause this way is tedious. probably there is an equation that would of made all of this simple

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