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dan815Best ResponseYou've already chosen the best response.0
are u having trouble with integrating functions with negative exponent or something?
 5 months ago

deepthiakella1Best ResponseYou've already chosen the best response.0
i thought it was u substitution
 5 months ago

dan815Best ResponseYou've already chosen the best response.0
no u can break it in to 3 pars so
 5 months ago

deepthiakella1Best ResponseYou've already chosen the best response.0
i didnt know you can do that to find the indef. integral
 5 months ago
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