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roselin
Group Title
what does the following mean? Calculate single ion activity coefficients for Cs^+, Cd^2+,Al^3+ and dissolved H2CO3 as a function of ionic strength for 10^4 lessthan equal I lessthan equal to1?
 8 months ago
 8 months ago
roselin Group Title
what does the following mean? Calculate single ion activity coefficients for Cs^+, Cd^2+,Al^3+ and dissolved H2CO3 as a function of ionic strength for 10^4 lessthan equal I lessthan equal to1?
 8 months ago
 8 months ago

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aaronq Group TitleBest ResponseYou've already chosen the best response.1
they want the activity coefficients for the different ions considering the ionic strength given
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
so from 10^4 to 1?
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
i am using the davies equation to calculate it, so each time I have to change the ionic strength th?
 8 months ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
hm no that doesn't seem right. i don't know what they mean by \(10^{4} \leq 1\), it doesn't make sense.
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
its \[10^{4}\le I \le1\]
 8 months ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
oh, i thought you typed the same thing twice accidentally. I guess they want it within that range? thats a large range though. I would graph it
 8 months ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
on excel of course
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
we have to calculate and plot it
 8 months ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
i guess do a few points for each ion and then plot it
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
can I show you the full question ? please tell me what I should do
 8 months ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
plug it into the formula? \(log\;\gamma=0.5Z^+_0Z^_0.. etc\) it's kinda weird though because they don't give you the negative counter ion
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
if I were to do this manually using that given range, how would I approach it?
 8 months ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
you would calculate the coefficient for several points (ionic strengths) do 3 or 4, then plot these. Activity coefficient on the y axis and ionic strength on the x axis (although you can do on which every way you want)
 8 months ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
it's much easier if you do it in excel though
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
yes, that is where I am having problem.
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
like that range is between 10^4 to 1 right?
 8 months ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
yep thats the range of "I" they gave
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
how would I calculte that in excel though?
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
if I do it manually then can I chose to do something like I= 10^4,10^3, 10^2 and 10^1?
 8 months ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
yeah thats fine
 8 months ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
for excel you need the x data point and the y data point the x you can just make up: 10^4, 10^3 then for the y you have to use the result from the equation, so you would type up the equation and use the x data points, then fill it. If you're not familiar with excel trying it this way might take you awhile
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
okay, thank you so much.
 8 months ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
no problem, good luck!
 8 months ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
thanks :)
 8 months ago
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