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roselin
Group Title
what does the following mean? Calculate single ion activity coefficients for Cs^+, Cd^2+,Al^3+ and dissolved H2CO3 as a function of ionic strength for 10^4 lessthan equal I lessthan equal to1?
 one year ago
 one year ago
roselin Group Title
what does the following mean? Calculate single ion activity coefficients for Cs^+, Cd^2+,Al^3+ and dissolved H2CO3 as a function of ionic strength for 10^4 lessthan equal I lessthan equal to1?
 one year ago
 one year ago

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aaronq Group TitleBest ResponseYou've already chosen the best response.1
they want the activity coefficients for the different ions considering the ionic strength given
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
so from 10^4 to 1?
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
i am using the davies equation to calculate it, so each time I have to change the ionic strength th?
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
hm no that doesn't seem right. i don't know what they mean by \(10^{4} \leq 1\), it doesn't make sense.
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
its \[10^{4}\le I \le1\]
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
oh, i thought you typed the same thing twice accidentally. I guess they want it within that range? thats a large range though. I would graph it
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
on excel of course
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
we have to calculate and plot it
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
i guess do a few points for each ion and then plot it
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
can I show you the full question ? please tell me what I should do
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
plug it into the formula? \(log\;\gamma=0.5Z^+_0Z^_0.. etc\) it's kinda weird though because they don't give you the negative counter ion
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
if I were to do this manually using that given range, how would I approach it?
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
you would calculate the coefficient for several points (ionic strengths) do 3 or 4, then plot these. Activity coefficient on the y axis and ionic strength on the x axis (although you can do on which every way you want)
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
it's much easier if you do it in excel though
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
yes, that is where I am having problem.
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
like that range is between 10^4 to 1 right?
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
yep thats the range of "I" they gave
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
how would I calculte that in excel though?
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
if I do it manually then can I chose to do something like I= 10^4,10^3, 10^2 and 10^1?
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
yeah thats fine
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
for excel you need the x data point and the y data point the x you can just make up: 10^4, 10^3 then for the y you have to use the result from the equation, so you would type up the equation and use the x data points, then fill it. If you're not familiar with excel trying it this way might take you awhile
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
okay, thank you so much.
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
no problem, good luck!
 one year ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
thanks :)
 one year ago
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