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johnny101

  • 2 years ago

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  1. jdoe0001
    • 2 years ago
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    hmmm \(\bf sin^{-1}(sin(\theta))\implies \theta\)

  2. jdoe0001
    • 2 years ago
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    as far as the range, yes, that's the default range constraints for the inverse sine

  3. jdoe0001
    • 2 years ago
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    but I don't think we can get an absolute angle value from that

  4. jdoe0001
    • 2 years ago
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    \(\bf y = sin(x)\implies sin^{-1}(y)=sin^{-1}(sin(x)\implies sin^{-1}(y)=x\)

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