Here's the question you clicked on:
johnny101

hmmm \(\bf sin^{1}(sin(\theta))\implies \theta\)
as far as the range, yes, that's the default range constraints for the inverse sine
but I don't think we can get an absolute angle value from that
\(\bf y = sin(x)\implies sin^{1}(y)=sin^{1}(sin(x)\implies sin^{1}(y)=x\)