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 one year ago
the vertices of a triangle are located at P (0,0), Q(8,6), R(3,4). what is the perimeter of this triangle
 one year ago
the vertices of a triangle are located at P (0,0), Q(8,6), R(3,4). what is the perimeter of this triangle

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Jusaquikie
 one year ago
Best ResponseYou've already chosen the best response.0Vertices atr the corner points. plot them out, since this triangle is not sitting on the x plane to find the length of each side you are going to have to use the Pythagorean theorem (a²+b²=c²) or better in the form \[\sqrt{a ^{2}+b ^{2}}=c\] so to find the length of line QR we have\[\sqrt{(8(3))^2+(64)^2}=\sqrt{11^2+2^2}=\sqrt{121+4}=\sqrt{125}=5\sqrt{5}\] now you can do PQ and PR, once you have the length of all three sides then add them together to get the perimeter.

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0Line RP is 5 Line RQ² = 4 + 121 = 125 Line RQ = 11.1803398875 Line PQ² = 64 + 36 = 100 PQ = 10 Perimeter = 5 + 11.1803398875 + 100 = 116.1803398875
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