anonymous
  • anonymous
This is the deal, I have two pulleys with a radii of 10.0in. and 6.00in., and their centers are 40.0 in. apart. If the pulley belt is uncrossed, what must be the length of the belt? Can somebody pull me to the side and please explain this to me, I also have a couple questions about this.
Trigonometry
schrodinger
  • schrodinger
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Jbo11
  • Jbo11
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Jbo11
  • Jbo11
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Jbo11
  • Jbo11
if so, here is a great step by step explanation http://frentzandsons.com/Hardware%20References/tofindthebeltlength.htm

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anonymous
  • anonymous
thank-you very much.
Jbo11
  • Jbo11
ok maybe bad example So in this you have two circles, you need to know the equation for the circumference of the circle which is 2pir^2 and use only half because the belt covers only half the circles then add the middle which is 40 but times by two because there's two lengths of it
anonymous
  • anonymous
before you go any farther, that site you gave to my is great. I've got the belt length needs to be 81.57inches. Did I do it right?
Jbo11
  • Jbo11
I got 131.2
Jbo11
  • Jbo11
so you use the diameters which are twice the radii so 20 and 12 add them, then multiply by 1.6, then add 40 twice
anonymous
  • anonymous
thats what i did wrong. i put the radii , not the diameter.
Jbo11
  • Jbo11
ah, yup, well as long as you understand the problem, little fixes like that can be checked and fixed
anonymous
  • anonymous
so how does the equation go??
anonymous
  • anonymous
2radii + 1/2pie +2length
Jbo11
  • Jbo11
yea
anonymous
  • anonymous
drum roll please........... I got belt length of 113.5in.
anonymous
  • anonymous
pellet it's not the same, what did I do wrong?
Jbo11
  • Jbo11
Oh ok your equation should be like (2radii+2radii)*1/2pi+2length
anonymous
  • anonymous
Would'nt you call that the circumference
Jbo11
  • Jbo11
yup, you are using half the circumference and then adding the length between the two pullys
anonymous
  • anonymous
half the circumference of each pully, so it be 32radii?
Jbo11
  • Jbo11
yea then times 1/2pi and add 80 gives you 131.2
anonymous
  • anonymous
thank-you so much.but I'm getting 130.27
anonymous
  • anonymous
I just recalculated and came up wth 131.2

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