The prop. blade of an airplane is 2.80ft, and rotates @ 2200 r/min. What is the linear velocity of a point on the tip of the blade?

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The prop. blade of an airplane is 2.80ft, and rotates @ 2200 r/min. What is the linear velocity of a point on the tip of the blade?

Trigonometry
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https://www.khanacademy.org/science/physics/torque-angular-momentum/torque-tutorial/v/relationship-between-angular-velocity-and-speed
Use \[v=\omega(r)=\theta/t(r)\] \[\theta = 2\pi rad\] t= 1 rev r = .5(2.8)
so them telling me the length of the blade holds no grounds?

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Will have to look up how to calculate linear velocity.
all I could find was angular velocity , and after about 2 hours on a simple problem hat
isnt linear velocity the speed of the circumference?
speed over time
I know there's a relationship between the two.
I found this: The formula for finding linear velocity is v = x / t. The x variable is distance traveled, and t is the time it took to travel the distance x. The v variable is the linear velocity. radius = 1.4 feet If prop rotates at 2,200 rev/min that equals 36.666 rev for every second Each turn of the prop means that the tip has traveled 1.4 *2*PI = 8.7964594301 feet Multiplying this by 36.666 rev per second equals 322.54 feet per second.
The distance from the prop center to the tip is half of 2.8 or 1.4 for each turn of the prop the tip must travel 1.4*2*PI feet.
so we take 2.80 and multiply in 1/2, that gives us half the blade length which is 1.4 ft. is that 1.4x2xpie?
which equals 8.7964594301 feet
now is that ft per second?
eventually it is feet per second. At this point we are only determining the distance traveled - which is 8.796 feet
persistence pays off i found my page
I'd like to thank ehuman and wolf1728, I couldn't have done it without you!
wait what am I talking about, im not done here.
(2200revs/min)(2 pi rad/rev)(1.4ft)=? that is the equation you need
compare it to what i gave you before

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