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Use
\[v=\omega(r)=\theta/t(r)\]
\[\theta = 2\pi rad\]
t= 1 rev
r = .5(2.8)

so them telling me the length of the blade holds no grounds?

Will have to look up how to calculate linear velocity.

all I could find was angular velocity , and after about 2 hours on a simple problem hat

isnt linear velocity the speed of the circumference?

speed over time

I know there's a relationship between the two.

which equals 8.7964594301 feet

now is that ft per second?

persistence pays off i found my page

I'd like to thank ehuman and wolf1728, I couldn't have done it without you!

wait what am I talking about, im not done here.

(2200revs/min)(2 pi rad/rev)(1.4ft)=?
that is the equation you need

compare it to what i gave you before