anonymous
  • anonymous
solve the quadratic equation. x^2-3x=4
Mathematics
katieb
  • katieb
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shamil98
  • shamil98
x^2 - 3x - 4 = 0 factor it.
swissgirl
  • swissgirl
We first need to set it up in the form \(ax^2+bx+c=0\)
swissgirl
  • swissgirl
Well ya like @shamil98 has shown we subtract 4 from both sides to achieve this

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anonymous
  • anonymous
Ok I got that. I have x^2-3x-4=0 but I am not sure where to go from there.
shamil98
  • shamil98
you can use the quadratic formula or just factor it to (x+b)(x-b) form. and then solve for (x+b)=0 and (x-b) = 0 to get your solutions
swissgirl
  • swissgirl
We need to find 2 numbers that when you add them they equal -3 and when you multiply them they equal -4
anonymous
  • anonymous
Well that would be -4 and 1.
shamil98
  • shamil98
correct.
swissgirl
  • swissgirl
Correct
shamil98
  • shamil98
so, in (x+b)(x-b)=0 form it would be?
swissgirl
  • swissgirl
So basically then we replace -3x with -4x +1x
swissgirl
  • swissgirl
So our equation would look as follows \(x^2-4x+1x-4\)
shamil98
  • shamil98
(x-4)(x+1) = 0 after you put it in that form x - 4 = 0 and x + 1 = 0 solve for x to get your solutions.
swissgirl
  • swissgirl
Then we group the first 2 terms and teh last 2 terms \( (x^2-4x)+(x-4)=0
swissgirl
  • swissgirl
\( (x^2-4x)+(x-4)=0\)
swissgirl
  • swissgirl
Then we factor out from each bracket x(x-4)+1(x-4)=0
shamil98
  • shamil98
You made a mistake I believe.. @swissgirl
swissgirl
  • swissgirl
At which point?
shamil98
  • shamil98
Well, she is asking how to find the solution, I have no idea what you are showing.. the original equation is x^2 - 3x - 4. factored out (x-4)(x+1)= 0 x = -1 x =4
shamil98
  • shamil98
x^2 - 4x + x -4 can just be simplified to x^2 -3x - 4 .....
swissgirl
  • swissgirl
Yes but I am just demonstrating how you factored it out This is the typical way it is taught in school and when it becomes more challenging then it is imperative that you write it out in this fashion
swissgirl
  • swissgirl
@Katelynmorris which method are you familiar with?
shamil98
  • shamil98
It looks more complicated with your method x^2 -3x -4 you know that the values are 1 and - 4. just put that like this (x-4)(x+1) = 0
anonymous
  • anonymous
I am lost after the x^2-4x+1x-4=0..Solving by factoring
swissgirl
  • swissgirl
But @shamil98 it works this time but what happens if the equation was \(3x^2-3x-4=0\) ?
anonymous
  • anonymous
Ok so after the (x-4)(x+1)=0 that gives me x how?
anonymous
  • anonymous
listen to sham, he got da plan @_@
shamil98
  • shamil98
(x-4)(x+1)=0 you put x-4=0 and x+1=0 to get your solutions .
anonymous
  • anonymous
@Katelynmorris just look at daht smart score of his @_@ YO SWISS, DONT BE CHEESY <3 I loe u, but let L do his Justice <3
shamil98
  • shamil98
3x2−3x−4=0 swiss, i would use the quadratic formula. instead of trying to factor it.
swissgirl
  • swissgirl
You can use whtvr it makes no diff as long as you get your answer
shamil98
  • shamil98
Your method is much more complicated than it needs to be, just make it simple..
swissgirl
  • swissgirl
The only reason why I was showing him that method since that is the method taught in schools
swissgirl
  • swissgirl
Plus your method wont work for complicated equations trust me kid
anonymous
  • anonymous
Ok so x= 4, -1?
shamil98
  • shamil98
Yes, those are your solutions.
anonymous
  • anonymous
Thanks.
anonymous
  • anonymous
as a drunk person on peaches, let me tell u somethin swiss cheese, sham aint no kid, he be Justice @_@
anonymous
  • anonymous
don't make me get my peaches loe <3 @Katelynmorris listen to sham, hes been doin dis for years @_@ just look at daht bronze 76 he got @_@
anonymous
  • anonymous
every time you type @_@ you tag whoever that is lol
anonymous
  • anonymous
LAWL XD
anonymous
  • anonymous
OMG THEY ACTUALLY EXCIST o-o
anonymous
  • anonymous
I have been using that face for so many times like this.........they will witness the spam of there lives when they come back XD
anonymous
  • anonymous
stalking profile now
anonymous
  • anonymous
XD

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