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Britt_d
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In a circle with a 12inch radius, find the length of a segment joining the midpoint of a 20inch chord and the center of the circle. x =
 8 months ago
 8 months ago
Britt_d Group Title
In a circle with a 12inch radius, find the length of a segment joining the midpoint of a 20inch chord and the center of the circle. x =
 8 months ago
 8 months ago

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jb1515g Group TitleBest ResponseYou've already chosen the best response.0
dw:1383721715330:dw
 8 months ago

jb1515g Group TitleBest ResponseYou've already chosen the best response.0
Use triangles to solve.
 8 months ago

Britt_d Group TitleBest ResponseYou've already chosen the best response.0
Pythagorean theorem?
 8 months ago

jb1515g Group TitleBest ResponseYou've already chosen the best response.0
That's your next step, yes. But it's also important that you understand how I set up that triangle to get to the Pythagorean theorem.
 8 months ago

Britt_d Group TitleBest ResponseYou've already chosen the best response.0
Ok this is really confusing how did you set it up?
 8 months ago

jb1515g Group TitleBest ResponseYou've already chosen the best response.0
Alright, so we know that the circle has radius 12, yes? So ANY point on the circle that connects with the center is 12. The chord is 20 inches long, and the definition of chord means that both end points touch the circle. We want to find the length of the segment connecting the MIDPOINT of the chord to the center, meaning that the chord will be split in half. That's where the 10 measurements came from. So one side of the triangle is 10, the other (from the center to the point on the chord) is the radius, or 12. That just leaves x. Clearer?
 8 months ago

Britt_d Group TitleBest ResponseYou've already chosen the best response.0
Yes so much more clear haha so \[x^{2}+10^{2}=12^{2}\] ?
 8 months ago

Britt_d Group TitleBest ResponseYou've already chosen the best response.0
Oh my gosh thank you so much! so it would be \[2\sqrt{22}\] ?
 8 months ago

jb1515g Group TitleBest ResponseYou've already chosen the best response.0
You might want to check your math on that last part. That's not what I got.
 8 months ago

Britt_d Group TitleBest ResponseYou've already chosen the best response.0
I'm not to sure what I did wrong......? I did 100144= 44 and then there isn't a perfect square for 44 so 44\2 = 22 so \[2\sqrt{22}\]
 8 months ago

jb1515g Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{44} =/= 2\sqrt{22}\]
 8 months ago

jb1515g Group TitleBest ResponseYou've already chosen the best response.0
Evaluate both numbers and see. Sqrt(44) is 6.63, 2*sqrt(22) is 9.38
 8 months ago

jb1515g Group TitleBest ResponseYou've already chosen the best response.0
Remember that \[\sqrt{ab} = \sqrt{a} * \sqrt{b}\] I think you just simplified the square root wrong.
 8 months ago

Britt_d Group TitleBest ResponseYou've already chosen the best response.0
Hmm ok so maybe \[2\sqrt{11}\] ?
 8 months ago

jb1515g Group TitleBest ResponseYou've already chosen the best response.0
Yeah, that's what I got.
 8 months ago

Britt_d Group TitleBest ResponseYou've already chosen the best response.0
Awesome I just forgot to simplify the 4 thank you!
 8 months ago

jb1515g Group TitleBest ResponseYou've already chosen the best response.0
Any time. Good job.
 8 months ago

wolf1728 Group TitleBest ResponseYou've already chosen the best response.0
Basically, you are calculating the length of the apothem. Go to the calculator here: http://1728.org/circsect.htm radius = 12 chord=20 calculator states the apothem = 6.6332 (which is 2 * sqroot(11))
 8 months ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
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 8 months ago
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