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mStudent002
 one year ago
) PLEASE HELP !!!!! You are asked to tutor a friend in algebra with adding and subtracting trinomials. Create an example of how to add two trinomials and how to subtract two trinomials. Come up with two trinomials and be sure to:
a. Write out each step used to complete each addition and subtraction example.
b. Show all the steps used to simplify the expressions.
c. Provide the resulting degree and classification of each example.
d. Explain why the polynomial is or is not closed over addition or subtraction based on the problem provided.
mStudent002
 one year ago
) PLEASE HELP !!!!! You are asked to tutor a friend in algebra with adding and subtracting trinomials. Create an example of how to add two trinomials and how to subtract two trinomials. Come up with two trinomials and be sure to: a. Write out each step used to complete each addition and subtraction example. b. Show all the steps used to simplify the expressions. c. Provide the resulting degree and classification of each example. d. Explain why the polynomial is or is not closed over addition or subtraction based on the problem provided.

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JuliaSarrazin
 one year ago
Best ResponseYou've already chosen the best response.2do you still need help on this?

mStudent002
 one year ago
Best ResponseYou've already chosen the best response.0could you help me ?

JuliaSarrazin
 one year ago
Best ResponseYou've already chosen the best response.2Addition: (3x^2+4x2) + (7x^210x+17) (add each part 3x^2 + 7x^2 = 4x^2 Then 4x + 10x = 6x Then 2+17= 15 So the answer to : (3x^2+4x2) + (7x^210x+17) is... 4x^2  6x + 15 (this is a second degree trinomial)

JuliaSarrazin
 one year ago
Best ResponseYou've already chosen the best response.2Subtraction: (3x^2+4x2)  (7x^210x+17) (subtract each part)  like terms 3x^2  7x^2= 10x^2 4x  10x= 14x 217= 19 So the answer to (3x^2+4x2)  (7x^210x+17) is.... 10x^2 + 14x  19x (second degree trinomial)

JuliaSarrazin
 one year ago
Best ResponseYou've already chosen the best response.2But im not really sure what d is asking...?

mStudent002
 one year ago
Best ResponseYou've already chosen the best response.0ok, thank you so much... & I'm not sure what its asking either.

Broskishelleh
 one year ago
Best ResponseYou've already chosen the best response.0@ImaGuest Do you need this?

ImaGuest
 one year ago
Best ResponseYou've already chosen the best response.0@Broskishelleh No, I don't

ImaGuest
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, I accidentaly opened this page looking for something else

ImaGuest
 one year ago
Best ResponseYou've already chosen the best response.0Didn't realize I still had it open

Broskishelleh
 one year ago
Best ResponseYou've already chosen the best response.0Oh, ok do you want to go back to your other question
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