A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 2 years ago
The massless bar, hinged at A, is inclined at an angle θ = 46.0° and subjected to horizontal and vertical forces F1 and F2, as shown. If L1 = 4.00 m, L2 = 1.00 m, F1 = 10 N, and the beam is in static equilibrium, what is the magnitude of F2?
anonymous
 2 years ago
The massless bar, hinged at A, is inclined at an angle θ = 46.0° and subjected to horizontal and vertical forces F1 and F2, as shown. If L1 = 4.00 m, L2 = 1.00 m, F1 = 10 N, and the beam is in static equilibrium, what is the magnitude of F2?

This Question is Closed

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1383951629230:dw Only the components of the force perpendicular to the bar (phi=90, psi=90) produce torque, so sum of the torques \[\sum \tau = \big(L_1F_1\sin\theta \big)\sin\phi  L_2F_2 \cos \theta\sin\psi =0\] solve for F2 I think

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Rewrite \[ \sum \tau = \big ( L_1 F_1 \sin \theta \big) \sin \varphi\big ( L_2 F_2 \cos \theta \big) \sin \psi=0\] \[F_2=\frac{\big ( L_1 F_1 \sin \theta \big)}{L_2\cos\theta}\] \[F_2=F_1\tan\theta\frac{L_1}{L_2}\] makes sense; if theta=0, F2 = 0 because F1 will supply no torque. If theta=90, F1 has to be zero or the function is undefined. hooray!

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0hmmm  there should be a negative sign there I think. blah :P

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Aha no it's correct no worries it worked out to be the right answer
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.