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When a falling meteoroid is at a distance above the Earth's surface of 3.20 times the Earth's radius, what is its acceleration due to the Earth's gravitational pull?
 5 months ago
 5 months ago
When a falling meteoroid is at a distance above the Earth's surface of 3.20 times the Earth's radius, what is its acceleration due to the Earth's gravitational pull?
 5 months ago
 5 months ago

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AllTehMaffsBest ResponseYou've already chosen the best response.1
\[R=3.2R_E\] \[g=G\frac{M_E}{(3.2R_E)^2}\]
 5 months ago

AllTehMaffsBest ResponseYou've already chosen the best response.1
RE = radius of the earth ME = mass of teh erf
 5 months ago

hhuummBest ResponseYou've already chosen the best response.0
so the radius of the earth is supposed to be a known thing?
 5 months ago

AllTehMaffsBest ResponseYou've already chosen the best response.1
yes. Both the mass and radius of the earth are known quantities. It should be either in your text book or google it.
 5 months ago
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