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swissgirl Group TitleBest ResponseYou've already chosen the best response.1
can theta=0 ? Like is is\[ 0< \theta <\Pi\] Or \[ 0 \leq \theta \leq \Pi\] ?
 8 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
0<θ<2Π has to be between this interval
 8 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
use substitution y=tan(theta/2) dw:1383969602615:dw
 8 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
0≤θ<2Π sorry correction, it has to be between this interval
 8 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
with a little bit of work you will find the solution
 8 months ago

Karina1 Group TitleBest ResponseYou've already chosen the best response.0
@Mertsj what about if they have a log like for example using the graph solve the system y=2x+3 and y=logx+1 im confused cause of the log
 8 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
@RED123url I am not sure what you did there...
 8 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
well y=tan(theta/2) sin(thata)= 2y/(y^2+1) cos(theta)=(1y^2)/(y^2+1) you know tan=sin/cos sec=1/cos plug things in and you will get an equation of y then go back y=tan)theta/2) and use the inverse
 8 months ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
The answer is 0 but I used trial and error
 8 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
@RED123url so just to confirm what swissgirl got, did you get the same answer?
 8 months ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
I graphed it to confirm my answer and its def right
 8 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
it should be 2pi
 8 months ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
Well it is 0 and 2 pi But if you noticed the interval is \[ 0 \leq \theta < 2\pi \]
 8 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
@RED123url well 2pi is not one the answers but 0 is, also according to the interval 2pi cannot be the answer..
 8 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
the real answer for these kind of problem involves n: the answer is 2npi. n can be 0 or any number even a billion
 8 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
@RED123url so would you agree that in this case the answer is 0?
 8 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
if 2pi is excluded of course
 8 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
well then. I am going with 0. Thank you both for your help!
 8 months ago
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