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swissgirl Group TitleBest ResponseYou've already chosen the best response.1
can theta=0 ? Like is is\[ 0< \theta <\Pi\] Or \[ 0 \leq \theta \leq \Pi\] ?
 11 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
0<θ<2Π has to be between this interval
 11 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
use substitution y=tan(theta/2) dw:1383969602615:dw
 11 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
0≤θ<2Π sorry correction, it has to be between this interval
 11 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
with a little bit of work you will find the solution
 11 months ago

Karina1 Group TitleBest ResponseYou've already chosen the best response.0
@Mertsj what about if they have a log like for example using the graph solve the system y=2x+3 and y=logx+1 im confused cause of the log
 11 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
@RED123url I am not sure what you did there...
 11 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
well y=tan(theta/2) sin(thata)= 2y/(y^2+1) cos(theta)=(1y^2)/(y^2+1) you know tan=sin/cos sec=1/cos plug things in and you will get an equation of y then go back y=tan)theta/2) and use the inverse
 11 months ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
The answer is 0 but I used trial and error
 11 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
@RED123url so just to confirm what swissgirl got, did you get the same answer?
 11 months ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
I graphed it to confirm my answer and its def right
 11 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
it should be 2pi
 11 months ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
Well it is 0 and 2 pi But if you noticed the interval is \[ 0 \leq \theta < 2\pi \]
 11 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
@RED123url well 2pi is not one the answers but 0 is, also according to the interval 2pi cannot be the answer..
 11 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
the real answer for these kind of problem involves n: the answer is 2npi. n can be 0 or any number even a billion
 11 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
@RED123url so would you agree that in this case the answer is 0?
 11 months ago

RED123url Group TitleBest ResponseYou've already chosen the best response.1
if 2pi is excluded of course
 11 months ago

Abdallah2012 Group TitleBest ResponseYou've already chosen the best response.0
well then. I am going with 0. Thank you both for your help!
 11 months ago
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