osanseviero
How to solve this?
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osanseviero
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\[10a ^{2}-20a+8\] Do I need to use the general formula?
hartnn
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solve ? if you want to solve you need an equation (with =0)
do you want to factor this ?
osanseviero
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yep
hartnn
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yes what ? factor or solve ?
osanseviero
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solve
hartnn
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then yes, you'll need a quadratic formula
hartnn
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Compare your quadratic equation with \(ax^2+bx+c=0\)
find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\]
then the two roots of x are:
\(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
osanseviero
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\[\frac{ -20\pm4\sqrt{5} }{ 20 }\]
osanseviero
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Am I correct until here?
hartnn
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b =-20
right ?
so, -b =+20
osanseviero
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Ok...and then?
hartnn
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yeah, then factor out the '4' from the numerator
osanseviero
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Thanks! Got it!
hartnn
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welcome ^_^