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osanseviero

  • 2 years ago

How to solve this?

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  1. osanseviero
    • 2 years ago
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    \[10a ^{2}-20a+8\] Do I need to use the general formula?

  2. hartnn
    • 2 years ago
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    solve ? if you want to solve you need an equation (with =0) do you want to factor this ?

  3. osanseviero
    • 2 years ago
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    yep

  4. hartnn
    • 2 years ago
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    yes what ? factor or solve ?

  5. osanseviero
    • 2 years ago
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    solve

  6. hartnn
    • 2 years ago
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    then yes, you'll need a quadratic formula

  7. hartnn
    • 2 years ago
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    Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

  8. osanseviero
    • 2 years ago
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    \[\frac{ -20\pm4\sqrt{5} }{ 20 }\]

  9. osanseviero
    • 2 years ago
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    Am I correct until here?

  10. hartnn
    • 2 years ago
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    b =-20 right ? so, -b =+20

  11. osanseviero
    • 2 years ago
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    Ok...and then?

  12. hartnn
    • 2 years ago
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    yeah, then factor out the '4' from the numerator

  13. osanseviero
    • 2 years ago
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    Thanks! Got it!

  14. hartnn
    • 2 years ago
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    welcome ^_^

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