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osanseviero Group TitleBest ResponseYou've already chosen the best response.1
\[10a ^{2}20a+8\] Do I need to use the general formula?
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
solve ? if you want to solve you need an equation (with =0) do you want to factor this ?
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes what ? factor or solve ?
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
then yes, you'll need a quadratic formula
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^24ac}=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{b \pm \sqrt{b^24ac}}{2a}}\)
 8 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ 20\pm4\sqrt{5} }{ 20 }\]
 8 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
Am I correct until here?
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
b =20 right ? so, b =+20
 8 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
Ok...and then?
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yeah, then factor out the '4' from the numerator
 8 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
Thanks! Got it!
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
welcome ^_^
 8 months ago
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