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osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1\[10a ^{2}20a+8\] Do I need to use the general formula?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1solve ? if you want to solve you need an equation (with =0) do you want to factor this ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yes what ? factor or solve ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1then yes, you'll need a quadratic formula

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^24ac}=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{b \pm \sqrt{b^24ac}}{2a}}\)

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 20\pm4\sqrt{5} }{ 20 }\]

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Am I correct until here?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1b =20 right ? so, b =+20

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yeah, then factor out the '4' from the numerator
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