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osanseviero
 one year ago
How to solve this?
osanseviero
 one year ago
How to solve this?

This Question is Closed

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1\[10a ^{2}20a+8\] Do I need to use the general formula?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1solve ? if you want to solve you need an equation (with =0) do you want to factor this ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yes what ? factor or solve ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1then yes, you'll need a quadratic formula

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^24ac}=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{b \pm \sqrt{b^24ac}}{2a}}\)

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 20\pm4\sqrt{5} }{ 20 }\]

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Am I correct until here?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1b =20 right ? so, b =+20

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yeah, then factor out the '4' from the numerator
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