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osanseviero Group Title

How to solve this?

  • 11 months ago
  • 11 months ago

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  1. osanseviero Group Title
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    \[10a ^{2}-20a+8\] Do I need to use the general formula?

    • 11 months ago
  2. hartnn Group Title
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    solve ? if you want to solve you need an equation (with =0) do you want to factor this ?

    • 11 months ago
  3. osanseviero Group Title
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    yep

    • 11 months ago
  4. hartnn Group Title
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    yes what ? factor or solve ?

    • 11 months ago
  5. osanseviero Group Title
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    solve

    • 11 months ago
  6. hartnn Group Title
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    then yes, you'll need a quadratic formula

    • 11 months ago
  7. hartnn Group Title
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    Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

    • 11 months ago
  8. osanseviero Group Title
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    \[\frac{ -20\pm4\sqrt{5} }{ 20 }\]

    • 11 months ago
  9. osanseviero Group Title
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    Am I correct until here?

    • 11 months ago
  10. hartnn Group Title
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    b =-20 right ? so, -b =+20

    • 11 months ago
  11. osanseviero Group Title
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    Ok...and then?

    • 11 months ago
  12. hartnn Group Title
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    yeah, then factor out the '4' from the numerator

    • 11 months ago
  13. osanseviero Group Title
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    Thanks! Got it!

    • 11 months ago
  14. hartnn Group Title
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    welcome ^_^

    • 11 months ago
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