osanseviero
  • osanseviero
How to solve this?
Mathematics
chestercat
  • chestercat
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osanseviero
  • osanseviero
\[10a ^{2}-20a+8\] Do I need to use the general formula?
hartnn
  • hartnn
solve ? if you want to solve you need an equation (with =0) do you want to factor this ?
osanseviero
  • osanseviero
yep

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hartnn
  • hartnn
yes what ? factor or solve ?
osanseviero
  • osanseviero
solve
hartnn
  • hartnn
then yes, you'll need a quadratic formula
hartnn
  • hartnn
Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
osanseviero
  • osanseviero
\[\frac{ -20\pm4\sqrt{5} }{ 20 }\]
osanseviero
  • osanseviero
Am I correct until here?
hartnn
  • hartnn
b =-20 right ? so, -b =+20
osanseviero
  • osanseviero
Ok...and then?
hartnn
  • hartnn
yeah, then factor out the '4' from the numerator
osanseviero
  • osanseviero
Thanks! Got it!
hartnn
  • hartnn
welcome ^_^

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