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PhoenixFire
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\[F(x)=\int _{ 1 }^{ ln(x^{ 2 }+e) }{ sin(e^{ t }) } dt\]
Find F'(x).
Not sure how to do this, I understand from the Fundamental Theorem of Calculus that
\[F'(x)=\frac { d }{ dx } \int _{ a }^{ x }{ f(t) } dt=f(x)\]
But what happens to the limit of \(ln(x^2+e)\)?
 9 months ago
 9 months ago
PhoenixFire Group Title
\[F(x)=\int _{ 1 }^{ ln(x^{ 2 }+e) }{ sin(e^{ t }) } dt\] Find F'(x). Not sure how to do this, I understand from the Fundamental Theorem of Calculus that \[F'(x)=\frac { d }{ dx } \int _{ a }^{ x }{ f(t) } dt=f(x)\] But what happens to the limit of \(ln(x^2+e)\)?
 9 months ago
 9 months ago

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bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
Don't you just do this: Sin(e^b)*(Sin(e^b)) ' where b is the upper limit.
 9 months ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
Well, you'd then subtract Sin(e^1) * (Sin(e^1))', but since the derivative of a constant is 0, this term becomes 0, and you're left with just the first one.
 9 months ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
Oh and by the way, e^(ln(x)) = x
 9 months ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.0
I don't understand why you're multiplying f(x) by f'(x) Or do you do the integration, and then derive it? \[\frac{d}{dx}(sin(e^{ln(x^2+e)})sin(e^1))=\frac{d}{dx}sin(x^2+e)=2xcos(x^2+e)=F'(x)\]
 9 months ago
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