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1668168

Use long division to find (10x^4+3x^3-x+5)/(2x+3).

  • 5 months ago
  • 5 months ago

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  1. zepdrix
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    |dw:1384225388681:dw|

    • 5 months ago
  2. zepdrix
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    So our goal is to match up the leading terms:|dw:1384225571316:dw|What do we want to multiply 2x by to turn it into 10x^4?

    • 5 months ago
  3. 1668168
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    @zepdrix so 2x*5x^3

    • 5 months ago
  4. zepdrix
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    Yes very good!|dw:1384225878362:dw|Understand what I did there? I multiplied `each` value by 5x^3

    • 5 months ago
  5. 1668168
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    @zepdrix yes I understand that part but what's the next step?

    • 5 months ago
  6. zepdrix
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    |dw:1384226367803:dw|Next we substract. You can either put a negative sign and brackets as I've done here, Or you can switch the sign of each term if that makes more sense to you. Just don't forget that the brackets let's us know that the subtraction is being distributed to each term.

    • 5 months ago
  7. 1668168
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    so it would be....-12 because the 10x^4 and x^3 are subtracted

    • 5 months ago
  8. zepdrix
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    |dw:1384226619653:dw|Ok good! Understand why we bring the x^3 down with it?

    • 5 months ago
  9. 1668168
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    no not really

    • 5 months ago
  10. zepdrix
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    |dw:1384226725590:dw|The x^3 is like the `name` of the things that we're subtracting.

    • 5 months ago
  11. zepdrix
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    We end up with 3 apples right? Not just 3. That doesn't tell us enough information.

    • 5 months ago
  12. 1668168
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    alright that makes more since so after -12x^3 ...

    • 5 months ago
  13. zepdrix
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    |dw:1384227065135:dw|We'll bring down the next term. Notice that I added a 0x^2 to the problem? We `can not` leave out a power of x. See how our powers jump from x^3 down to x? We have to include the x^2 term so I wrote a 0x^2 as a placeholder.

    • 5 months ago
  14. zepdrix
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    |dw:1384227185855:dw|Now we repeat the process again, we want to match these circled terms.

    • 5 months ago
  15. 1668168
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    -14 but what about x in this one?

    • 5 months ago
  16. zepdrix
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    to get from 2 to -12 I guess we would need to multiply by -6 yes? And to get from x to x^3 we need to multiply by x^2

    • 5 months ago
  17. zepdrix
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    |dw:1384227627979:dw|So what do we get on our next line? :)

    • 5 months ago
  18. 1668168
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    so then I multiply -6x^2 *2x+3=-12x-18x^2

    • 5 months ago
  19. zepdrix
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    -12x^3-18x^2 is what you meant I assume? Ok good, then we subtract!|dw:1384228134036:dw|

    • 5 months ago
  20. 1668168
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    sorry i keep forgetting the x^3

    • 5 months ago
  21. 1668168
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    so 18^2

    • 5 months ago
  22. zepdrix
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    |dw:1384228374212:dw|Ok good!

    • 5 months ago
  23. 1668168
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    is this the answer 5x3-6x2+9x-14 i finished it

    • 5 months ago
  24. zepdrix
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    Oh sorry I ran off for a sec :) I dunno lemme check real quick.

    • 5 months ago
  25. zepdrix
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    Ok looks good! Did you end up with any remainder?

    • 5 months ago
  26. 1668168
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    yeah of 47

    • 5 months ago
  27. zepdrix
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    Yay good job! \c:/

    • 5 months ago
  28. 1668168
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    thanks for all help...you are a lifesaver

    • 5 months ago
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