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1668168 Group Title

Use long division to find (10x^4+3x^3-x+5)/(2x+3).

  • one year ago
  • one year ago

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  1. zepdrix Group Title
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    |dw:1384225388681:dw|

    • one year ago
  2. zepdrix Group Title
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    So our goal is to match up the leading terms:|dw:1384225571316:dw|What do we want to multiply 2x by to turn it into 10x^4?

    • one year ago
  3. 1668168 Group Title
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    @zepdrix so 2x*5x^3

    • one year ago
  4. zepdrix Group Title
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    Yes very good!|dw:1384225878362:dw|Understand what I did there? I multiplied `each` value by 5x^3

    • one year ago
  5. 1668168 Group Title
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    @zepdrix yes I understand that part but what's the next step?

    • one year ago
  6. zepdrix Group Title
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    |dw:1384226367803:dw|Next we substract. You can either put a negative sign and brackets as I've done here, Or you can switch the sign of each term if that makes more sense to you. Just don't forget that the brackets let's us know that the subtraction is being distributed to each term.

    • one year ago
  7. 1668168 Group Title
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    so it would be....-12 because the 10x^4 and x^3 are subtracted

    • one year ago
  8. zepdrix Group Title
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    |dw:1384226619653:dw|Ok good! Understand why we bring the x^3 down with it?

    • one year ago
  9. 1668168 Group Title
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    no not really

    • one year ago
  10. zepdrix Group Title
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    |dw:1384226725590:dw|The x^3 is like the `name` of the things that we're subtracting.

    • one year ago
  11. zepdrix Group Title
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    We end up with 3 apples right? Not just 3. That doesn't tell us enough information.

    • one year ago
  12. 1668168 Group Title
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    alright that makes more since so after -12x^3 ...

    • one year ago
  13. zepdrix Group Title
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    |dw:1384227065135:dw|We'll bring down the next term. Notice that I added a 0x^2 to the problem? We `can not` leave out a power of x. See how our powers jump from x^3 down to x? We have to include the x^2 term so I wrote a 0x^2 as a placeholder.

    • one year ago
  14. zepdrix Group Title
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    |dw:1384227185855:dw|Now we repeat the process again, we want to match these circled terms.

    • one year ago
  15. 1668168 Group Title
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    -14 but what about x in this one?

    • one year ago
  16. zepdrix Group Title
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    to get from 2 to -12 I guess we would need to multiply by -6 yes? And to get from x to x^3 we need to multiply by x^2

    • one year ago
  17. zepdrix Group Title
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    |dw:1384227627979:dw|So what do we get on our next line? :)

    • one year ago
  18. 1668168 Group Title
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    so then I multiply -6x^2 *2x+3=-12x-18x^2

    • one year ago
  19. zepdrix Group Title
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    -12x^3-18x^2 is what you meant I assume? Ok good, then we subtract!|dw:1384228134036:dw|

    • one year ago
  20. 1668168 Group Title
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    sorry i keep forgetting the x^3

    • one year ago
  21. 1668168 Group Title
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    so 18^2

    • one year ago
  22. zepdrix Group Title
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    |dw:1384228374212:dw|Ok good!

    • one year ago
  23. 1668168 Group Title
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    is this the answer 5x3-6x2+9x-14 i finished it

    • one year ago
  24. zepdrix Group Title
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    Oh sorry I ran off for a sec :) I dunno lemme check real quick.

    • one year ago
  25. zepdrix Group Title
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    Ok looks good! Did you end up with any remainder?

    • one year ago
  26. 1668168 Group Title
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    yeah of 47

    • one year ago
  27. zepdrix Group Title
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    Yay good job! \c:/

    • one year ago
  28. 1668168 Group Title
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    thanks for all help...you are a lifesaver

    • one year ago
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