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Use long division to find (10x^4+3x^3-x+5)/(2x+3).

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So our goal is to match up the leading terms:|dw:1384225571316:dw|What do we want to multiply 2x by to turn it into 10x^4?
@zepdrix so 2x*5x^3

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Yes very good!|dw:1384225878362:dw|Understand what I did there? I multiplied `each` value by 5x^3
@zepdrix yes I understand that part but what's the next step?
|dw:1384226367803:dw|Next we substract. You can either put a negative sign and brackets as I've done here, Or you can switch the sign of each term if that makes more sense to you. Just don't forget that the brackets let's us know that the subtraction is being distributed to each term.
so it would be....-12 because the 10x^4 and x^3 are subtracted
|dw:1384226619653:dw|Ok good! Understand why we bring the x^3 down with it?
no not really
|dw:1384226725590:dw|The x^3 is like the `name` of the things that we're subtracting.
We end up with 3 apples right? Not just 3. That doesn't tell us enough information.
alright that makes more since so after -12x^3 ...
|dw:1384227065135:dw|We'll bring down the next term. Notice that I added a 0x^2 to the problem? We `can not` leave out a power of x. See how our powers jump from x^3 down to x? We have to include the x^2 term so I wrote a 0x^2 as a placeholder.
|dw:1384227185855:dw|Now we repeat the process again, we want to match these circled terms.
-14 but what about x in this one?
to get from 2 to -12 I guess we would need to multiply by -6 yes? And to get from x to x^3 we need to multiply by x^2
|dw:1384227627979:dw|So what do we get on our next line? :)
so then I multiply -6x^2 *2x+3=-12x-18x^2
-12x^3-18x^2 is what you meant I assume? Ok good, then we subtract!|dw:1384228134036:dw|
sorry i keep forgetting the x^3
so 18^2
|dw:1384228374212:dw|Ok good!
is this the answer 5x3-6x2+9x-14 i finished it
Oh sorry I ran off for a sec :) I dunno lemme check real quick.
Ok looks good! Did you end up with any remainder?
yeah of 47
Yay good job! \c:/
thanks for all are a lifesaver

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