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How do you factor sin^3x + cos^3x?

Mathematics
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Do you know how to factor a sum of cubes?
There is a cute formula for it.
\[a^3+b^3=(a+b)(a^2-ab+b^2)\]

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Other answers:

Looks cute lol thank you
lol. Do you know how to use it with the trig functions?
\[(\sin(x))^3+(\cos(x))^3=a^3+b^3 \]
should be easy for you to determine what is a and what is b.
if it isn't then let me know so i can explain further
I've got the equation down but what to do first?
Do I multiply what's in the parenthesis?
no
tell me what a is and what b is based on what I wrote above
A is sin and b is cos
\[(\sin(x))^3+(\cos(x))^3=a^3+b^3 \]
ok so just go to the other side of the formula and replace a with sin(x) and replace b with cos(x) and then you are done don't do nothing more
I did :)
ok then you are done sir
\[a^3+b^3=(a+b)(a^2-ab+b^2) \] everywhere we seen an a we put sin(x) everywhere we seen a b we put cos(x)
Thanks!
np :)
I will have another question in a moment
k

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