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ChristopherW28

  • 2 years ago

How do you factor sin^3x + cos^3x?

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  1. myininaya
    • 2 years ago
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    Do you know how to factor a sum of cubes?

  2. myininaya
    • 2 years ago
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    There is a cute formula for it.

  3. myininaya
    • 2 years ago
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    \[a^3+b^3=(a+b)(a^2-ab+b^2)\]

  4. ChristopherW28
    • 2 years ago
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    Looks cute lol thank you

  5. myininaya
    • 2 years ago
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    lol. Do you know how to use it with the trig functions?

  6. myininaya
    • 2 years ago
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    \[(\sin(x))^3+(\cos(x))^3=a^3+b^3 \]

  7. myininaya
    • 2 years ago
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    should be easy for you to determine what is a and what is b.

  8. myininaya
    • 2 years ago
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    if it isn't then let me know so i can explain further

  9. ChristopherW28
    • 2 years ago
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    I've got the equation down but what to do first?

  10. ChristopherW28
    • 2 years ago
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    Do I multiply what's in the parenthesis?

  11. myininaya
    • 2 years ago
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    no

  12. myininaya
    • 2 years ago
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    tell me what a is and what b is based on what I wrote above

  13. ChristopherW28
    • 2 years ago
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    A is sin and b is cos

  14. myininaya
    • 2 years ago
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    \[(\sin(x))^3+(\cos(x))^3=a^3+b^3 \]

  15. myininaya
    • 2 years ago
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    ok so just go to the other side of the formula and replace a with sin(x) and replace b with cos(x) and then you are done don't do nothing more

  16. ChristopherW28
    • 2 years ago
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    I did :)

  17. myininaya
    • 2 years ago
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    ok then you are done sir

  18. myininaya
    • 2 years ago
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    \[a^3+b^3=(a+b)(a^2-ab+b^2) \] everywhere we seen an a we put sin(x) everywhere we seen a b we put cos(x)

  19. ChristopherW28
    • 2 years ago
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    Thanks!

  20. myininaya
    • 2 years ago
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    np :)

  21. ChristopherW28
    • 2 years ago
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    I will have another question in a moment

  22. myininaya
    • 2 years ago
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    k

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