Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
ChristopherW28
Group Title
Verify that (1cos^2x)(1+cos^2x)=2sin^2xsin^4x is a trig identity
 8 months ago
 8 months ago
ChristopherW28 Group Title
Verify that (1cos^2x)(1+cos^2x)=2sin^2xsin^4x is a trig identity
 8 months ago
 8 months ago

This Question is Closed

myininaya Group TitleBest ResponseYou've already chosen the best response.1
By a certain Pythagorean identity we can say 1cos^2(x)=?
 8 months ago

ChristopherW28 Group TitleBest ResponseYou've already chosen the best response.0
Sin^2x?
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
so this means we now have \[\sin^2(x)(1+\cos^2(x))=2\sin^2(x)\sin^4(x)\] now this is an identity we are trying to prove now we have one side in terms of sin and another side in terms of mixture of sin and cos
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
We could use that same identity to rewrite cos^2(x)
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[1\cos^2(x)=\sin^2(x) => \cos^2(x)=\]
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
that is a blank for you to fill in
 8 months ago

ChristopherW28 Group TitleBest ResponseYou've already chosen the best response.0
I'm lost
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Ok I want to rewrite cos^2(x) because the other side is just in terms of sin I know an identity that has cos^2(x) and sin^2(x) in it.
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\cos^2(x)+\sin^2(x)=1 \]
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
So cos^2(x)=?
 8 months ago

ChristopherW28 Group TitleBest ResponseYou've already chosen the best response.0
Sin^x+ 1
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
1sin^2(x)
 8 months ago

ChristopherW28 Group TitleBest ResponseYou've already chosen the best response.0
Sin^2x+1?
 8 months ago

ChristopherW28 Group TitleBest ResponseYou've already chosen the best response.0
I was close
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
1cos^2(x)=sin^2(x) 1sin^2(x)=cos^2(x) cos^2(x)+sin^2(x)=1
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
So we can back to what we are trying to prove and replace the cos^2(x) with 1sin^2(x) \[\sin^2(x)(1+(1\sin^2(x))=2\sin^2(x)\sin^4(x)\]
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I replaced mr.cos^2(x) with mrs. (1sin^2(x))
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
now we don't need those parenthesis since there is a + in front of that parenthesis lets drop that extra stuff giving us: \[\sin^2(x)(1+1\sin^2(x))=2\sin^2(x)\sin^4(x) \]
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
now 1+1=2 which I know you know (:p) so now you distribute on that left hand side
 8 months ago

ChristopherW28 Group TitleBest ResponseYou've already chosen the best response.0
I gtg I can figure out what's left. Friend me on Facebook @ Christopher McElhannon. I will need your help again :)
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I will be here most likely. I'm not much of a facebook user. I'm on facebook free diet right now. :p
 8 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.