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OMAR91
Group Title
I am trying to find evalues and evectors of the matrix:
[2 3
2 2]
I found that ʎ= √2 i
Then when trying to find the evector I was stuck at
V= [2√2 i 3
2 2√2i]
How do I find V ???
 10 months ago
 10 months ago
OMAR91 Group Title
I am trying to find evalues and evectors of the matrix: [2 3 2 2] I found that ʎ= √2 i Then when trying to find the evector I was stuck at V= [2√2 i 3 2 2√2i] How do I find V ???
 10 months ago
 10 months ago

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amistre64 Group TitleBest ResponseYou've already chosen the best response.1
[2x 3 2 2x] (2x)(2x) 3(2) 2(2x)x(2x) +6 4+2x 2x +x^2 +6 x^2  2 = 0; x = + sqrt2 right?
 10 months ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
your right, the i is there ... forgot how to subtract for a sec
 10 months ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
you do an rref now right?
 10 months ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
or: (AL)x = 0 (2√2 i)x + 3y = 0 2x+(2√2i)y = 0 we can setup a system of equations to solve for x and y
 10 months ago

OMAR91 Group TitleBest ResponseYou've already chosen the best response.0
As I took in class, I should find a value to multiply it by the first row so the first element in the 2nd row becomes 0. Then it is in rowechelon form and the rest is easy...
 10 months ago

OMAR91 Group TitleBest ResponseYou've already chosen the best response.0
Sorry I mean after multiplying something by the 1st row AND ADDING to the 2nd row, the 1st element of the 2nd row should become 0
 10 months ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
we get something like: 1 1+i/sqrt2 0 0 x = (1+i/sqrt2)y
 10 months ago

OMAR91 Group TitleBest ResponseYou've already chosen the best response.0
How is that?
 10 months ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i take it you are not good at row reductions?
 10 months ago

OMAR91 Group TitleBest ResponseYou've already chosen the best response.0
I'm not good at math! :(
 10 months ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
im gonna use a instead of isqrt2, in either case its simply an unknown amount 2a 3 2 2a swap rows, not needed but its viable 2 2a 2a 3 divide row 1 by 2 1 1+a/2 2a 3 multiply row 1 by 2+a and add the results to row 2 2+a (1+a/2)(2+a) 2a 3  0 (1+a/2)(2+a) + 3 1(2+a)+(a/2(2+a) + 3 2 a + a + a^2/2 + 3 a^2/2 + 1 now we might want to address that a = isqrt2 (i)^2 2/2 + 1 (i)^2 + 1 1 + 1 = 0 these leaves as as: 1 1+a/2 0 0 therefore: x = y(1a/2)
 10 months ago

OMAR91 Group TitleBest ResponseYou've already chosen the best response.0
AWSOME! Thanks a lot...
 10 months ago
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