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mathcalculus

  • 2 years ago

HELP :( Determine the equation of the line tangent to the graph of y= 18 e^{9 x} at x=0

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  1. dhouser
    • 2 years ago
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    you need to take the derivative of y d/dx (18*e^(9x))

  2. mathcalculus
    • 2 years ago
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    162e^9x

  3. dhouser
    • 2 years ago
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    so your slope is 162*e^0 = 162

  4. dhouser
    • 2 years ago
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    derivative = slope

  5. mathcalculus
    • 2 years ago
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    got cha =]

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