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mathcalculus

  • 2 years ago

HELP -PLEASE :(!! y=13e^(3x^2)-6x at x=3 in the form y=mx +b has

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  1. tkhunny
    • 2 years ago
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    You will need the 1st Derivative.

  2. ranga
    • 2 years ago
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    Check your first derivative again. Or you can show how you got that.

  3. anonymous
    • 2 years ago
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    \[f'(x)=117xe^{3x^2}-6\] right?

  4. mathcalculus
    • 2 years ago
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    how'd you get that?

  5. mathcalculus
    • 2 years ago
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    i thought f'(x)= 78xe^(3x^2)-6

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