mathcalculus
HELP PLEASE :(!!
y=13e^(3x^2)6x
at x=3 in the form y=mx +b has



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tkhunny
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You will need the 1st Derivative.

ranga
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Check your first derivative again. Or you can show how you got that.

anonymous
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\[f'(x)=117xe^{3x^2}6\] right?

mathcalculus
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how'd you get that?

mathcalculus
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i thought f'(x)= 78xe^(3x^2)6