1. LaynaMae

2. SSmiles

what is this algebra 1b or 1a

3. LaynaMae

Ummm ... what ? Lol

4. LaynaMae

Idk ? It's Algebra 2 ..

5. fbi2015

6. LaynaMae

It's all one question , sir .

7. LaynaMae

It's a project . Can't be posted separately , that's stupid .

8. JAMG

well to start you need 3 points, A B C to which your spacecraft will travel, since the problem says you can pick them pick any of them

9. LaynaMae

Okay so would (2, -3) (2,4) and (5,4) work ?

10. JAMG

ok lets have (2,3) instead of 2,-3 since that its saying that your plane its up in the air goes down and lifts up

11. LaynaMae

Oh .. okay .. haha my bad .

12. JAMG

:D, ok next we need to plot points including the point of launching in a graph

13. LaynaMae

Okay so we're going to plot the points I picked ?

14. JAMG

yes including the launch point

15. LaynaMae

Yes I know lol

16. LaynaMae

Am I drawing that or something ?

17. JAMG

well since its a project you need to show your work and graphing paper should have been provided to you

18. LaynaMae

I do my schooling online ..

19. JAMG

well, you need it on paper to determine the next step which is the first question, give your equation in standard form from laucnch pad to point A

20. LaynaMae

I honestly don't know how to do that ..

21. JAMG

standard form requires where the line crosses the x and y axis and its way easier to see if its graphed

22. LaynaMae

I am going to have to draw a graph then I suppose

23. JAMG

yes

24. LaynaMae

Ok drew the graph and plotted the points

25. LaynaMae

And the launch point ...

26. JAMG

connect your point A to the launch point and extended to cross the y and x axis

27. JAMG

it should cross at 0,1 and -1,0

28. LaynaMae

Close enough , I drew it myself to of course it's not spot on

29. JAMG

so your equation should be y = x + 1 now to put it in standard form we need to move the x to the left of the equation

30. LaynaMae

Okay so that should look like y = 1 + x ?

31. LaynaMae

NOOO

32. LaynaMae

Sorrry I read it wrong , should look like x = y + 1 ?

33. JAMG

not exactly, it should be to the left of the equal sign only the x so y = x + 1 y - x = x + 1 - x y - x = 1

34. JAMG

and thats your answer for the first question y - x = 1

35. LaynaMae

Oh okay , that makes more sense .. Hah let me record the information in my document real quick

36. LaynaMae

Done

37. JAMG

your next question is point slope form so you need your point B and the slope from point A to point B point slop form: y -y1 = m( x -x1)

38. LaynaMae

Okay so that would look like ... y - 3 = m (x-2) ?

39. JAMG

i think your point B is 2,4 so it should the 3 should be a 4

40. LaynaMae

Oh I thought you said point A .. Confusion .. My bad

41. JAMG

lets change your point B to 3,4 that way its makes sense to go in a nice even trajectory

42. JAMG

so your eqation should be y - 4 = (x -3)

43. LaynaMae

So I should change that everywhere then ?

44. JAMG

sure its your points it makes your equations easier to do because you are going to have to explain how the trajectory is going later on

45. LaynaMae

Ohh okay , well i changed it

46. JAMG

we havent use it so its ok for now

47. LaynaMae

Okay

48. halorazer

Well I mean I would have said something but you know, I've been warned by moderators twice today that I am too helpful and that I shouldn't give people the answers after going through and showing every step I took and explaining them. Because all we need in this world are some moderators that want to inhibit the learning process.

49. LaynaMae

@halorazer OMG haha that cracked me up ... But I've been in that position and I hated it .. I'm really sorry :( Its like being in jail in a way lol ..

50. LaynaMae

@JAMG BE RIGHT BACK ! Please don't go anywhere , just going to get my dinner and come back .

51. halorazer

Because answering hundreds of questions in a few days is the wrong thing to do. I'm sorry Open Study developers, I am helping the people on your website. I am so sorry for answering roughly 100 questions in 3 days, I am sorry if I did not go to college for 6 years to do the exact same thing that I'm doing now. Oops. Guilty as charged.

52. LaynaMae

Omg , that was just perfect .. You're so right though .. But I've gotta get back to this project , message me if you'd like :) @JAMG I'm back !

53. halorazer

Anyways, I don't care about them. What's the project? :3 I'd love to help.

54. JAMG

ok, we are goint from point B = (3,4) to C = (5,4) and this time we need point intercept form which is y = mx + b

55. JAMG

you can do the last questions :D

56. LaynaMae

@halorazer Basically I just need to answer the questions above with the information I have . Which would be by 3 points , A B and C . I'm on the 3rd question now :)

57. LaynaMae

@JAMG You're not going to help me no more ? :'c

58. JAMG

59. LaynaMae

You both can help ..? :'o

60. JAMG

ok your slope = m =( y2 - y1) / (x2 - x1)

61. halorazer

I'm a he. You can do this. I will probably get banned for trying. D; Good luck. I will be watching from the shadows. >:D

62. LaynaMae

I have to go for like 10 minutes you guys !! PLEASE DO NOT LEAVE ME D:

63. JAMG

sorry, have a picture of a she so i assume which is bad :(

64. halorazer

It's okay. :3 I would think the same thing too.

65. LaynaMae

Never mind , I'm back .

66. LaynaMae

@JAMG So that would look like this .... m = (4 - 4) / (5 - 2)

67. JAMG

yes , so what do you notice about the top number

68. LaynaMae

Top number ?

69. JAMG

4 - 4

70. LaynaMae

That would equal 0

71. LaynaMae

UGH Be right back again .... 10 min max I swear :( PLEASE DO NOT LEAVE DD:

72. LaynaMae

I"M BACK

73. LaynaMae

NOOOOOO @JAMG YOU LEFT :((((

74. halorazer

I'm present.

75. LaynaMae

So ... you can help me finish this God forsaken project ? :D

76. halorazer

As long as I don't get banned first ;)

77. LaynaMae

You should be okay :p

78. halorazer

Okay, so where were you guys?

79. LaynaMae

Question 3 :) & I already wrote out the equation so maybe we're on question 4 now O.o

80. halorazer

m = (4 - 4) / (5 - 2)?

81. LaynaMae

Yepp !

82. halorazer

0/3=m 0=m Therefore, the slope of this is equal to 0, and is is a horizontal line.

83. halorazer

this is *

84. halorazer

There's like a hundred messages so can you like give me the points and whatever, and the question? >.<

85. LaynaMae

Lol yes , the points are A(2,3) B(3,4) and C(5,4) . The current question we're on is number 4 so that would be "In question 2, you selected one of two points (Point A or Point B) to be included in your point-slope equation. Write the point-slope form of that equation again, using the other point’s coordinates."

86. halorazer

What point did you guys use?

87. LaynaMae

Point B

88. halorazer

What was the slope? I am gonna need that. :p I'd rather not have to recalculate the slope between a and b.

89. LaynaMae

The slope ? :o

90. halorazer

Yes.

91. LaynaMae

The slope of what ? We didn't establish a slope ..? :o

92. halorazer

You should have? o.o

93. LaynaMae

We didn't D:

94. halorazer

A(2,3) B(3,4) y2-y1/x2-x1 4-3/3-2=1/1 =1 m=1

95. halorazer

y-3=1(x-2) y-3=x-2 +3 y=x+1

96. LaynaMae

Oh snap ... it makes sense now ... Let me go back and change everything in my document .. 1 minute !

97. halorazer

I hate your project. I hate it. Srsly.

98. LaynaMae

Wait what question is that for ? And dude you're not the only one . I've put off doing this project since Unit 1 ... I'm on Unit 3 now ...

99. halorazer

Oh my god where is everyone. I'm gonna get yelled at for anything I say so you know what. @ranga can you help her?

100. LaynaMae

:'c

101. halorazer

Where's the other person like why did he have to leave us here

102. LaynaMae

I'm saying ... I clearly told him not to leave , that I would be right back ... And I was ..

103. ranga

Reading this problem and all the other replies is like reading a novel. It is gonna be a while...

104. LaynaMae

3 more freakin questions and I am done .... Omg ... C':

105. halorazer

Or you can tell yourself what I tell myself everyday. "Do it tomorrow."

106. LaynaMae

Lol I think I might actually be able to finish on my own .. Other dude helped with all the Albert Einstein questions

107. LaynaMae

I am on questions 7 and 8 now

108. halorazer

ranga, always the man who knows what's up.

109. LaynaMae

Lol I see that , I just need help with the last 2 questions now . 7. 7. Reflect back on this scenario and each equation you created. Would any restrictions apply to the domain and range of those equations? Explain your reasoning using complete sentences. 8. 8. Explain, using complete sentences, why it is important to understand any limitations on the domain and range.

110. LaynaMae

@ranga Are you able to help me with these ?

111. ranga

I was answering another question. This one is just too long to read through the entire problem and all the replies. But without going thru all of it, the restrictions I can think of is x and y should not be negative.

112. LaynaMae

Oh okay , well thank you

113. ranga

Can't be 100% sure if that is what they are expecting unless I read through the whole thing and give it some thought. Maybe the spacecraft shouldn't even be below the launch point.

114. LaynaMae

I don't know .. I'm going to make something up for them and submit this dang thing . Tired of it . Thank you to everyone that helped me <3

115. halorazer

Plus 20 to ranga.

116. ranga

y measures the vertical height. Therefore y cannot be negative. Maybe y shouldn't even be below the launch point. Therefore range will be either (0, infinity) or [2, infinity) To find the domain for each equation, set the condition y > 0 and solve for x. The upper bound will be infinity. So the domain for each function will look like: (a, infinity) where you have to find the value of "a" for each equation that will ensure y > 0.