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anonymous
 2 years ago
ANYONE ??????
Log the coordinates of the specific points in space to which your spacecraft will travel. Please remember to include the graph of your points and the lines connecting each point along with your work.
Launch Area:___(1, 2)___
Point A:__________
Point B:__________
Point C:__________
You must show your work on each question below.
Determine the equation of the line, in standard form, that will get your spacecraft from the Launch Area to Point A.
Determine the equation of the line, in pointslope form, that will get your spacecraft from Point A to Point B.
Determine the equation of the line, in slopeintercept form, that will get your spacecraft from Point B to Point C.
In question 2, you selected one of two points (Point A or Point B) to be included in your pointslope equation. Write the pointslope form of that equation again, using the other point’s coordinates.
Convert the equations you arrived at in question 2 and question 4 into slopeintercept form.
Does the point you select matter when your write a pointslope equation? Explain your reasoning using complete sentences.
Reflect back on this scenario and each equation you created. Would any restrictions apply to the domain and range of those equations? Explain your reasoning using complete sentences.
Explain, using complete sentences, why it is important to understand any limitations on the domain and range.
anonymous
 2 years ago
ANYONE ?????? Log the coordinates of the specific points in space to which your spacecraft will travel. Please remember to include the graph of your points and the lines connecting each point along with your work. Launch Area:___(1, 2)___ Point A:__________ Point B:__________ Point C:__________ You must show your work on each question below. Determine the equation of the line, in standard form, that will get your spacecraft from the Launch Area to Point A. Determine the equation of the line, in pointslope form, that will get your spacecraft from Point A to Point B. Determine the equation of the line, in slopeintercept form, that will get your spacecraft from Point B to Point C. In question 2, you selected one of two points (Point A or Point B) to be included in your pointslope equation. Write the pointslope form of that equation again, using the other point’s coordinates. Convert the equations you arrived at in question 2 and question 4 into slopeintercept form. Does the point you select matter when your write a pointslope equation? Explain your reasoning using complete sentences. Reflect back on this scenario and each equation you created. Would any restrictions apply to the domain and range of those equations? Explain your reasoning using complete sentences. Explain, using complete sentences, why it is important to understand any limitations on the domain and range.

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0what is this algebra 1b or 1a

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Idk ? It's Algebra 2 ..

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Try to post one question per thread next time, please.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0It's all one question , sir .

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0It's a project . Can't be posted separately , that's stupid .

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0well to start you need 3 points, A B C to which your spacecraft will travel, since the problem says you can pick them pick any of them

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Okay so would (2, 3) (2,4) and (5,4) work ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0ok lets have (2,3) instead of 2,3 since that its saying that your plane its up in the air goes down and lifts up

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Oh .. okay .. haha my bad .

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0:D, ok next we need to plot points including the point of launching in a graph

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Okay so we're going to plot the points I picked ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yes including the launch point

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Am I drawing that or something ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0well since its a project you need to show your work and graphing paper should have been provided to you

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I do my schooling online ..

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0well, you need it on paper to determine the next step which is the first question, give your equation in standard form from laucnch pad to point A

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I honestly don't know how to do that ..

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0standard form requires where the line crosses the x and y axis and its way easier to see if its graphed

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I am going to have to draw a graph then I suppose

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Ok drew the graph and plotted the points

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0And the launch point ...

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0connect your point A to the launch point and extended to cross the y and x axis

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0it should cross at 0,1 and 1,0

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Close enough , I drew it myself to of course it's not spot on

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0so your equation should be y = x + 1 now to put it in standard form we need to move the x to the left of the equation

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Okay so that should look like y = 1 + x ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Sorrry I read it wrong , should look like x = y + 1 ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0not exactly, it should be to the left of the equal sign only the x so y = x + 1 y  x = x + 1  x y  x = 1

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0and thats your answer for the first question y  x = 1

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Oh okay , that makes more sense .. Hah let me record the information in my document real quick

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0your next question is point slope form so you need your point B and the slope from point A to point B point slop form: y y1 = m( x x1)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Okay so that would look like ... y  3 = m (x2) ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i think your point B is 2,4 so it should the 3 should be a 4

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Oh I thought you said point A .. Confusion .. My bad

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0lets change your point B to 3,4 that way its makes sense to go in a nice even trajectory

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0so your eqation should be y  4 = (x 3)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So I should change that everywhere then ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0sure its your points it makes your equations easier to do because you are going to have to explain how the trajectory is going later on

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Ohh okay , well i changed it

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0we havent use it so its ok for now

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Well I mean I would have said something but you know, I've been warned by moderators twice today that I am too helpful and that I shouldn't give people the answers after going through and showing every step I took and explaining them. Because all we need in this world are some moderators that want to inhibit the learning process.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@halorazer OMG haha that cracked me up ... But I've been in that position and I hated it .. I'm really sorry :( Its like being in jail in a way lol ..

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@JAMG BE RIGHT BACK ! Please don't go anywhere , just going to get my dinner and come back .

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Because answering hundreds of questions in a few days is the wrong thing to do. I'm sorry Open Study developers, I am helping the people on your website. I am so sorry for answering roughly 100 questions in 3 days, I am sorry if I did not go to college for 6 years to do the exact same thing that I'm doing now. Oops. Guilty as charged.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Omg , that was just perfect .. You're so right though .. But I've gotta get back to this project , message me if you'd like :) @JAMG I'm back !

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Anyways, I don't care about them. What's the project? :3 I'd love to help.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0ok, we are goint from point B = (3,4) to C = (5,4) and this time we need point intercept form which is y = mx + b

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0you can do the last questions :D

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@halorazer Basically I just need to answer the questions above with the information I have . Which would be by 3 points , A B and C . I'm on the 3rd question now :)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@JAMG You're not going to help me no more ? :'c

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0hehe, she said she wanted to help you

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0You both can help ..? :'o

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0ok your slope = m =( y2  y1) / (x2  x1)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I'm a he. You can do this. I will probably get banned for trying. D; Good luck. I will be watching from the shadows. >:D

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I have to go for like 10 minutes you guys !! PLEASE DO NOT LEAVE ME D:

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0sorry, have a picture of a she so i assume which is bad :(

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0It's okay. :3 I would think the same thing too.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Never mind , I'm back .

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@JAMG So that would look like this .... m = (4  4) / (5  2)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yes , so what do you notice about the top number

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0UGH Be right back again .... 10 min max I swear :( PLEASE DO NOT LEAVE DD:

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0NOOOOOO @JAMG YOU LEFT :((((

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So ... you can help me finish this God forsaken project ? :D

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0As long as I don't get banned first ;)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0You should be okay :p

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Okay, so where were you guys?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Question 3 :) & I already wrote out the equation so maybe we're on question 4 now O.o

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0m = (4  4) / (5  2)?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.00/3=m 0=m Therefore, the slope of this is equal to 0, and is is a horizontal line.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0There's like a hundred messages so can you like give me the points and whatever, and the question? >.<

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Lol yes , the points are A(2,3) B(3,4) and C(5,4) . The current question we're on is number 4 so that would be "In question 2, you selected one of two points (Point A or Point B) to be included in your pointslope equation. Write the pointslope form of that equation again, using the other point’s coordinates."

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0What point did you guys use?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0What was the slope? I am gonna need that. :p I'd rather not have to recalculate the slope between a and b.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0The slope of what ? We didn't establish a slope ..? :o

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0A(2,3) B(3,4) y2y1/x2x1 43/32=1/1 =1 m=1

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0y3=1(x2) y3=x2 +3 y=x+1

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Oh snap ... it makes sense now ... Let me go back and change everything in my document .. 1 minute !

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I hate your project. I hate it. Srsly.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Wait what question is that for ? And dude you're not the only one . I've put off doing this project since Unit 1 ... I'm on Unit 3 now ...

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Oh my god where is everyone. I'm gonna get yelled at for anything I say so you know what. @ranga can you help her?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Where's the other person like why did he have to leave us here

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I'm saying ... I clearly told him not to leave , that I would be right back ... And I was ..

ranga
 2 years ago
Best ResponseYou've already chosen the best response.1Reading this problem and all the other replies is like reading a novel. It is gonna be a while...

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.03 more freakin questions and I am done .... Omg ... C':

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Or you can tell yourself what I tell myself everyday. "Do it tomorrow."

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Lol I think I might actually be able to finish on my own .. Other dude helped with all the Albert Einstein questions

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I am on questions 7 and 8 now

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0ranga, always the man who knows what's up.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Lol I see that , I just need help with the last 2 questions now . 7. 7. Reflect back on this scenario and each equation you created. Would any restrictions apply to the domain and range of those equations? Explain your reasoning using complete sentences. 8. 8. Explain, using complete sentences, why it is important to understand any limitations on the domain and range.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@ranga Are you able to help me with these ?

ranga
 2 years ago
Best ResponseYou've already chosen the best response.1I was answering another question. This one is just too long to read through the entire problem and all the replies. But without going thru all of it, the restrictions I can think of is x and y should not be negative.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Oh okay , well thank you

ranga
 2 years ago
Best ResponseYou've already chosen the best response.1Can't be 100% sure if that is what they are expecting unless I read through the whole thing and give it some thought. Maybe the spacecraft shouldn't even be below the launch point.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I don't know .. I'm going to make something up for them and submit this dang thing . Tired of it . Thank you to everyone that helped me <3

ranga
 2 years ago
Best ResponseYou've already chosen the best response.1y measures the vertical height. Therefore y cannot be negative. Maybe y shouldn't even be below the launch point. Therefore range will be either (0, infinity) or [2, infinity) To find the domain for each equation, set the condition y > 0 and solve for x. The upper bound will be infinity. So the domain for each function will look like: (a, infinity) where you have to find the value of "a" for each equation that will ensure y > 0.
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