## shycarterrr 2 years ago what is an equation of the line that passes through the point (-4,-1) and is parallel to and perpendicular to the line 2x+7y=14 ?

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1. shycarterrr

2. Karebear_Karl

$y=\frac{ 7x }{ 2 }+15$

3. monty5658

you want two different equations? one for parallell and one for perpendicular? Note: parallel has same slope, and perpendicular has negative reciprocal of slope. The primary equation in slope intercept form should be y = -2/7x + 2

4. monty5658

So using the equation formula. (y-y1)=m(x-x1). You plug in your points from (-4,-1) and the slope you need (see above for parallel or perpendicular). Parallel. (y+1)=-2/7(x+4) : use algebra and get x and y on left of equation. Note, the +4 and +1 are due to -(-1) and -(-4). Perpendicular. Same thing in a sense, but the slope must be the negative reciprocal of the primary equation (line). (y+1)=7/2(x+4) again, use algebra and get the x and y on left side of equation.

5. monty5658

Therefore: Parallel: 7y+2x=-15 Perpendicular: 2y-7x=26

6. alinalynn

need to know how to work this equation for the parallel i am not understanding fully...y=-5/3x+2...please help