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shycarterrr
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what is an equation of the line that passes through the point (4,1) and is parallel to and perpendicular to the line 2x+7y=14 ?
 8 months ago
 8 months ago
shycarterrr Group Title
what is an equation of the line that passes through the point (4,1) and is parallel to and perpendicular to the line 2x+7y=14 ?
 8 months ago
 8 months ago

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shycarterrr Group TitleBest ResponseYou've already chosen the best response.0
I NEED HELP ASAP PLEASEE
 8 months ago

Karebear_Karl Group TitleBest ResponseYou've already chosen the best response.1
\[y=\frac{ 7x }{ 2 }+15\]
 8 months ago

monty5658 Group TitleBest ResponseYou've already chosen the best response.1
you want two different equations? one for parallell and one for perpendicular? Note: parallel has same slope, and perpendicular has negative reciprocal of slope. The primary equation in slope intercept form should be y = 2/7x + 2
 8 months ago

monty5658 Group TitleBest ResponseYou've already chosen the best response.1
So using the equation formula. (yy1)=m(xx1). You plug in your points from (4,1) and the slope you need (see above for parallel or perpendicular). Parallel. (y+1)=2/7(x+4) : use algebra and get x and y on left of equation. Note, the +4 and +1 are due to (1) and (4). Perpendicular. Same thing in a sense, but the slope must be the negative reciprocal of the primary equation (line). (y+1)=7/2(x+4) again, use algebra and get the x and y on left side of equation.
 8 months ago

monty5658 Group TitleBest ResponseYou've already chosen the best response.1
Therefore: Parallel: 7y+2x=15 Perpendicular: 2y7x=26
 8 months ago

alinalynn Group TitleBest ResponseYou've already chosen the best response.0
need to know how to work this equation for the parallel i am not understanding fully...y=5/3x+2...please help
 7 months ago
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