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shycarterrr
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what is an equation of the line that passes through the point (4,1) and is parallel to and perpendicular to the line 2x+7y=14 ?
 10 months ago
 10 months ago
shycarterrr Group Title
what is an equation of the line that passes through the point (4,1) and is parallel to and perpendicular to the line 2x+7y=14 ?
 10 months ago
 10 months ago

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shycarterrr Group TitleBest ResponseYou've already chosen the best response.0
I NEED HELP ASAP PLEASEE
 10 months ago

Karebear_Karl Group TitleBest ResponseYou've already chosen the best response.1
\[y=\frac{ 7x }{ 2 }+15\]
 10 months ago

monty5658 Group TitleBest ResponseYou've already chosen the best response.1
you want two different equations? one for parallell and one for perpendicular? Note: parallel has same slope, and perpendicular has negative reciprocal of slope. The primary equation in slope intercept form should be y = 2/7x + 2
 10 months ago

monty5658 Group TitleBest ResponseYou've already chosen the best response.1
So using the equation formula. (yy1)=m(xx1). You plug in your points from (4,1) and the slope you need (see above for parallel or perpendicular). Parallel. (y+1)=2/7(x+4) : use algebra and get x and y on left of equation. Note, the +4 and +1 are due to (1) and (4). Perpendicular. Same thing in a sense, but the slope must be the negative reciprocal of the primary equation (line). (y+1)=7/2(x+4) again, use algebra and get the x and y on left side of equation.
 10 months ago

monty5658 Group TitleBest ResponseYou've already chosen the best response.1
Therefore: Parallel: 7y+2x=15 Perpendicular: 2y7x=26
 10 months ago

alinalynn Group TitleBest ResponseYou've already chosen the best response.0
need to know how to work this equation for the parallel i am not understanding fully...y=5/3x+2...please help
 9 months ago
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