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anonymous
 3 years ago
when serving in tennis a player tosses the tennis ball vertically in the . The height h of the ball after t seconds is given by the quadratic function h(t)=5t^2+7t (the height is measured in meters from the point of the toss.)
a. How high in the air does the ball go?
b. Assume that the player hits the ball on its way down when it's 0.6m above the point of the toss. For how many seconds is the ball in the air between the toss and the serve?
I've already got 7/2x(5)=7/10.7
anonymous
 3 years ago
when serving in tennis a player tosses the tennis ball vertically in the . The height h of the ball after t seconds is given by the quadratic function h(t)=5t^2+7t (the height is measured in meters from the point of the toss.) a. How high in the air does the ball go? b. Assume that the player hits the ball on its way down when it's 0.6m above the point of the toss. For how many seconds is the ball in the air between the toss and the serve? I've already got 7/2x(5)=7/10.7

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ranga
 3 years ago
Best ResponseYou've already chosen the best response.0For part a) h(t)=5t^2+7t =5(t^2  7/5t) complete the square of the expression in parenthesis to put the function in the vertex form. Then comparing it to standard vertex form: h = a(th)^2 + k where (h,k) is the vertex. Identify k and that will be how high the ball goes.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I already told you I have .7

ranga
 3 years ago
Best ResponseYou've already chosen the best response.0First you put that under b. Secondly, that is not k. You have h.

ranga
 3 years ago
Best ResponseYou've already chosen the best response.0plug in t = .7 in h(t)=5t^2+7t and calculate h

dan815
 3 years ago
Best ResponseYou've already chosen the best response.0there used to be constantly questions about slopes and lines now i see these questions a lot

dan815
 3 years ago
Best ResponseYou've already chosen the best response.0when you throw a ball up in the air at the highest point its velocity = 0 as it is goes up going up to down, so somwhere in there it has 0 speed and velocity

dan815
 3 years ago
Best ResponseYou've already chosen the best response.0so h'(t) = velocity set h'(t) = 0 and solve

dan815
 3 years ago
Best ResponseYou've already chosen the best response.0that tells you the time it takes to get to highest veloicty then see what distance you travel given that time substituting that time into h(t)

dan815
 3 years ago
Best ResponseYou've already chosen the best response.0that highest point*, with 0 velocity

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ranga I got 5.145 for h. Is that right?

ranga
 3 years ago
Best ResponseYou've already chosen the best response.0Try again. Don't forget there is a negative sign in front of t^2.

ranga
 3 years ago
Best ResponseYou've already chosen the best response.05t^2+7t 5(0.7)^2 + 7(.7) = ?

ranga
 3 years ago
Best ResponseYou've already chosen the best response.0You can evaluate that using your calculator.

ranga
 3 years ago
Best ResponseYou've already chosen the best response.0BTW, the notifications are not working for a couple of days and so people may not be notified when tagged or a reply is posted. Yes 2.45 meters is correct for a) For b) substitute h = 0.6 in h(t) = 5t^2+7t and solve for t. You will get two values for t  the ball reaches 0.65 meters once while going up and once while coming down. Choose the higher t because they want the value when the ball is coming down.
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