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y = -2x^2 - 20x - 48

You subtracted 100 though ^

you add 48 to the other side and then also the 100 and the quadratic = 148

then you can factor the left side

can you show me that in steps? like from the beginning

you did it rite just set the equation = 0
then subtract 49 from both sides so
2x^2-20x=48

then complete the square and add the 100 to both sides

so it'd be 0 = -2(x^2 - 20x + 100) -48 ?

why do I need to factor that

Ok I got it thanks! and one more question

How would I solve:
x^2 - 38x + c
also by completing the square

c is a constant most likely just move it to the other side and complete the square

what is that going to give me?

x^2-38x=c

and what would be the next step

0 = (x2 - 38x ___) +c ?

square the -38 and do the same to both sides

(x^2-38x+__)=__-c

-38/2 = -19^2 = 361

yup

so that is on both sides

(x^2-38x+361)=361-c

okay so far i have:
(x^2 - 38x + 361) = 361 -c

right now you should be able to factor the quadratic
which is the point of completing the square

so like:
____ x___ = 361
____+___= -38

right
it will be the same number it is squared

-19

yup

(x-19)^2 = 361 - c?

and the first equation was x^2-10+25=49

right

what do I do now?

with the second you can't do anything it is most likely to show how you did the work

x-5=7

so just that ^

how would i write tht in intercept form

do you mean y=mx+b

no I also have to rewrite tht in intercept

the x intercept is +or-(7/5,0)

that is the y is 0