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whadduptori
Solve triangle ABC given that A= 56 degrees B=57 degrees and b =9
cosine of B divided by sine b = cosine of A divided by sidea
Try the Law of Sines. |dw:1384735024017:dw|
sin(57 °) / 9 = sin(56 °) / a @whadduptori Solve for a. Get the measure of <C from the theorem that the sum of the interior angles of a triangle is 180. Then, use the Law of Sines again to get side AB.