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whadduptori

  • 2 years ago

Solve triangle ABC given that A= 56 degrees B=57 degrees and b =9

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  1. Decart
    • 2 years ago
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    law of cosines

  2. Decart
    • 2 years ago
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    cosine of B divided by sine b = cosine of A divided by sidea

  3. Directrix
    • 2 years ago
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    Try the Law of Sines. |dw:1384735024017:dw|

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  4. Directrix
    • 2 years ago
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    sin(57 °) / 9 = sin(56 °) / a @whadduptori Solve for a. Get the measure of <C from the theorem that the sum of the interior angles of a triangle is 180. Then, use the Law of Sines again to get side AB.

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