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oboe

  • 2 years ago

1/6^x+2=216 How do you solve for x?

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  1. DemolisionWolf
    • 2 years ago
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    do I understrand the equation right? \[\frac {1}{6^x+2}=216 \]

  2. Decart
    • 2 years ago
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    log?

  3. oboe
    • 2 years ago
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    it's and expodentail x+2 instead of 6^x and then add 2 to all of it. And we haven't been taught the log method yet.

  4. DemolisionWolf
    • 2 years ago
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    so this? \[\frac {1}{6^{x+2}}=216\]

  5. DemolisionWolf
    • 2 years ago
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    \[\frac {1} {6^x} + 2 = 216\]

  6. ranga
    • 2 years ago
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    I think it is: \[\Large \frac{ 1 }{ 6^{x+2} } = 216\]

  7. Decart
    • 2 years ago
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    \[\left( 1/6 \right)^{x+2}=216\]

  8. ranga
    • 2 years ago
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    216 = 6^3

  9. DemolisionWolf
    • 2 years ago
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    3 different ways it can be read...and the 'question asker' isn't even here...

  10. ranga
    • 2 years ago
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    6^(-x-2) = 6^3 -x-2 = 3 x = -5

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