## anonymous 3 years ago 1/6^x+2=216 How do you solve for x?

1. anonymous

do I understrand the equation right? $\frac {1}{6^x+2}=216$

2. anonymous

log?

3. anonymous

it's and expodentail x+2 instead of 6^x and then add 2 to all of it. And we haven't been taught the log method yet.

4. anonymous

so this? $\frac {1}{6^{x+2}}=216$

5. anonymous

$\frac {1} {6^x} + 2 = 216$

6. ranga

I think it is: $\Large \frac{ 1 }{ 6^{x+2} } = 216$

7. anonymous

$\left( 1/6 \right)^{x+2}=216$

8. ranga

216 = 6^3

9. anonymous

3 different ways it can be read...and the 'question asker' isn't even here...

10. ranga

6^(-x-2) = 6^3 -x-2 = 3 x = -5