oboe
1/6^x+2=216 How do you solve for x?



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DemolisionWolf
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do I understrand the equation right?
\[\frac {1}{6^x+2}=216 \]

Decart
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log?

oboe
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it's and expodentail x+2 instead of 6^x and then add 2 to all of it. And we haven't been taught the log method yet.

DemolisionWolf
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so this?
\[\frac {1}{6^{x+2}}=216\]

DemolisionWolf
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\[\frac {1} {6^x} + 2 = 216\]

ranga
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I think it is:
\[\Large \frac{ 1 }{ 6^{x+2} } = 216\]

Decart
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\[\left( 1/6 \right)^{x+2}=216\]

ranga
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216 = 6^3

DemolisionWolf
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3 different ways it can be read...and the 'question asker' isn't even here...

ranga
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6^(x2) = 6^3
x2 = 3
x = 5