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Jwoolcock

  • 2 years ago

how do you write the square root of -232 in terms of i

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  1. compphysgeek
    • 2 years ago
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    with \(i^2 = -1\) you can say that \(-232 = i^2 \times 232\) and therefore \(\sqrt{-232} = i\,\sqrt{232}\)

  2. SnuggieLad
    • 2 years ago
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    See, i is the square root of a -1 In order to remove it you just take out the negative so it would be \[i \sqrt{232}\]

  3. SnuggieLad
    • 2 years ago
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    Then you just take the square root of 232 and write it beside the i leaving the remainder inside the radical

  4. SnuggieLad
    • 2 years ago
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    \[radical = \sqrt{(number here)} <---\]

  5. Jwoolcock
    • 2 years ago
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    thank you

  6. SnuggieLad
    • 2 years ago
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    Don't forget to medal the best answer.

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