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Jwoolcock
how do you write the square root of -232 in terms of i
with \(i^2 = -1\) you can say that \(-232 = i^2 \times 232\) and therefore \(\sqrt{-232} = i\,\sqrt{232}\)
See, i is the square root of a -1 In order to remove it you just take out the negative so it would be \[i \sqrt{232}\]
Then you just take the square root of 232 and write it beside the i leaving the remainder inside the radical
\[radical = \sqrt{(number here)} <---\]
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