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TortoiseAvenger
 2 years ago
In the solution to the problem following session 8, it reads
"We know that 1 is less than or equal to sin(x) which is less than or equal to 1."
I'm good with this, but then it reads:
"So it must be true that:"
1/x is less than or equal to sin(x)/x which is less than or equal to 1/x.
I don't understand (algebraically) this could be true of all values of x. Can someone please explain?
TortoiseAvenger
 2 years ago
In the solution to the problem following session 8, it reads "We know that 1 is less than or equal to sin(x) which is less than or equal to 1." I'm good with this, but then it reads: "So it must be true that:" 1/x is less than or equal to sin(x)/x which is less than or equal to 1/x. I don't understand (algebraically) this could be true of all values of x. Can someone please explain?

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creeksider
 2 years ago
Best ResponseYou've already chosen the best response.1If you begin with the inequality stated after "We know that," and multiply every term by 1/x, we get the inequality stated after "So it must be true that." We're just multiplying through by 1/x. You might wonder how we can get away with this, for two reasons. One is the problem at x=0, and the solution acknowledges that we don't have a clear understanding of what happens there. The other is what happens when x turns negative, because multiplying an inequality by a negative number changes the direction of the inequality. That doesn't happen here, which I guess can be explained by the fact that sin(x)=sin(x).

TortoiseAvenger
 2 years ago
Best ResponseYou've already chosen the best response.0Ok. So I understand the algebra now. Thanks! However, I'm a little confused about the "x turns negative" situation. Can you possibly explain this further? Thanks again, TA

creeksider
 2 years ago
Best ResponseYou've already chosen the best response.1I probably caused unnecessary confusion with that remark, just thinking out loud about the general rule that when you multiply an inequality by a negative number, the inequality reverses direction. For example, x>4 implies that x<4. That made me wonder why we can multiply by 1/x through this inequality and have it work even when 1/x is negative. It doesn't cause a problem here so we don't have to worry about it.

TortoiseAvenger
 2 years ago
Best ResponseYou've already chosen the best response.0Stab in the dark here... could it be that any negative angle can be expressed as a positive angle? I seem to remember this "excuse" being used somewhere else in trig.

WaltlaW
 2 years ago
Best ResponseYou've already chosen the best response.0I think interchanging negative and positive angle relationships might really depend on the application at hand.
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