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mathcalculus

  • 2 years ago

HELP PLEASE :( !! y=13e^(3x^2)-6x at x=3 in the form y=mx +b has

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  1. mathcalculus
    • 2 years ago
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    so for f '(x)= I got 78xe^(3x^2)-6

  2. mathcalculus
    • 2 years ago
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    @amistre64

  3. amistre64
    • 2 years ago
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    im assuming you notated it correctly ... f = 13 e^(3x^2) - 6x f' = 13*3*2x e^(3x^2) - 6 find f'(3) and f(3) to build the line with: y = f'(3)(x-3) + f'(3)

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