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mathcalculus
 one year ago
PLEASE HELP :( !!
y=13e^(3x^2)6x
at x=3 in the form y=mx +b has
mathcalculus
 one year ago
PLEASE HELP :( !! y=13e^(3x^2)6x at x=3 in the form y=mx +b has

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mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0f'(x)= 78xe^(3x^2)6

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0slope= 234e^276 y=13e^2718

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2So you're looking for an equation of the line tangent to the curve f(x) at x=3?

akotto4897
 one year ago
Best ResponseYou've already chosen the best response.0omg this is so simple

akotto4897
 one year ago
Best ResponseYou've already chosen the best response.0wat is america coming to

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0yes, Determine the equation of the line tangent to the graph of

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0yeah but I'm not sure why I'm getting this wrong.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2@akotto4897 wtf is wrong with you? Why would you call someone elses problem `so simple`. It's like someone in 5th grade calling 3rd grade math SUPER EASY! Just because you understand it doesn't mean that everyone else is on your level...

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Ok that's enough of my rant :) lemme check your work a sec :3

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0lol, i appreciate that. but yes, let's begin.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Mmm ok so your slope looks good. So what coordinate pair are we using to find our yintercept?\[\Large f(3)\quad=\quad 13e^{27}18\]Mmm ok ok I see you have the written down already :3 \[\Large y_{\tan}\quad=\quad mx+b\]So if we plug in our coordinate pair, we get something like this, yes?\[\Large 13e^{27}18\quad=\quad (234e^{27}6)\cdot 3+b\]

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0woah so the slope is good and the y too.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0oh i see there's an x there.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0so would it be 247e^2718?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2for your y_tan? or for b?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Hmm after you find your b value, you should plug it back into the \[\Large\bf y_{tan}\quad=\quad \color{royalblue}{m}x+\color{royalblue}{b}\] For our final answer, we DON'T want the coordinate pair plugged in. We're only trying to fill in these blue pieces.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0so how do i get to the answer.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0at first i thought it was 247e^27 6x

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2grr sorry website crashed on me >:c

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i just don't understand what to do at the point slope formula.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i keep getting the answer wrong.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large\bf y_{\tan}\quad=\quad \color{royalblue}{m}x+\color{royalblue}{b}\]Plugging in our slope,\[\Large\bf y_{\tan}\quad=\quad \color{royalblue}{(234e^{27}6)}x+\color{royalblue}{b}\]Then we plug in our coordinate pair to find b,\[\Large\bf \color{#DD4747 }{13e^{27}18}\quad=\quad \color{royalblue}{(234e^{27}6)}\cdot\color{#DD4747 }{3}+\color{royalblue}{b}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2So we have some 18's cancelling out. And I think we get a b value of,\[\Large\bf \color{royalblue}{b\quad=\quad 689e^{27}}\]Something like that?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0isn't it y(13e^2718)=234e^276x+18

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0right, yy1=m(xx1)

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0so in this case, slope= 234e^276 y=13e^2718

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2No that's `pointslope` form of a line. yy1 = m( xx1) We don't want to use that. We were told to use the `slopeintercept` form of a line. y=mx+b

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0can we do it the way i had it please?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0yeah but i thought i could use that to find the equation of a tangent line

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0I've been using that for other problems and it worked.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Yes we can use that, so let's see if we can get it set up correctly. Lemme see if I can match what you wrote a sec :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large\bf yy_1\quad=\quad \color{royalblue}{m}(xx_1)\]\[\Large\bf yy_1\quad=\quad \color{royalblue}{(234e^{27}6)}(xx_1)\]Then plugging in our point:\[\Large\bf y\color{#DD4747 }{(13e^{27}18)}\quad=\quad \color{royalblue}{(234e^{27}6)}(x\color{#DD4747 }{3})\]

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0after that I'm lost lol

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Ok so now we just need to get in into the form y=mx+b. So we need to multiply out the brackets, then we gotta isolate the y term.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\bf y\color{#DD4747 }{(13e^{27}18)}\quad=\quad 234e^{27}x6x 702e^{27}+18\]I think it expands like that, yes? Give it a try :)

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0yup, but i seem to be doing that wrong unfortunately.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0wait don't we just multiply out the 6 and 6*3 only?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Yes, true. We probably want don't want the x's expanded like that,\[\large\bf y\color{#DD4747 }{(13e^{27}18)}\quad=\quad (234e^{27}6)x 702e^{27}+18\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large 234e^{27}\cdot3\]

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0why don't we multiply 234e^27 with x?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\bf (234e^{27}6)(x3)\quad=\\ \large\bf\quad (234e^{27}6)x(234e^{27}6)3\]And we only want to multiply out the part with the 3.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0im so confused. i do't understand why we did this problem differently than all the others when it comes to this part.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0so for (234e^27−6)(x−3) i thought we do foil

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Yes, foiling should give you this,\[\large\bf 234e^{27}x6x 702e^{27}+18\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Are you not getting that when you foil..?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0yes i have that! :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2We don't want multiple x terms, so we'll factor an x out of each of the first two terms.\[\Large\bf =\quad \large\bf (234e^{27}6)x 702e^{27}+18\]

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0where does my foiling go?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0great so we factor?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2We had this,\[\Large\bf y\color{#DD4747 }{(13e^{27}18)}\quad=\quad \color{royalblue}{(234e^{27}6)}(x\color{#DD4747 }{3})\]It foiled to give us this,\[\large\bf y(13e^{27}18)\quad=\quad 234e^{27}x6x 702e^{27}+18\]We factored out an x to give us this,\[\large\bf y(13e^{27}18)\quad=\quad (234e^{27}6)x 702e^{27}+18\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2We finish by solving for y.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\bf y=\\\large\bf (234e^{27}6)x 702e^{27}+18+13e^{27}18\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2the 6 and the 18 are not like terms, we can't combine those.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2I don't know why you insisted on using pointslope form for this one. It seems way more complicated :c

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0but it's the only way for me… i have to stick to this or else i'll be completely lost in the exam

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2This one only ended up being complicated because our slope was `2 terms`. So it ended up being a ton of multiplication.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0damn im so confused.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0what would be he answer btw?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\bf y(13e^{27}18)\quad=\quad (234e^{27}6)x 702e^{27}+18\]From here: you add (13e^{27}18) to each side,\[\large\bf y=\\ \large\bf(234e^{27}6)x 702e^{27}+18\color{orangered}{+(13e^{27}18)}\]Does that step make sense? +_+ That's how we isolate the y term.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2From there we can drop the brackets since nothing in being applied to them, \[\large\bf y=\\ \large\bf(234e^{27}6)x 702e^{27}+18+13e^{27}18\]It looks like the 18's will cancel out,\[\large\bf y=\\ \large\bf(234e^{27}6)x 702e^{27}+\cancel{18}+13e^{27}\cancel{18}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2And the exponential terms ( not the one attached to the x ) are like terms, so we'll combine them,\[\large\bf y=\\ \large\bf(234e^{27}6)x \color{orangered}{702e^{27}+13e^{27}}\] \[\large\bf y=(234e^{27}6)x \color{orangered}{689e^{27}}\]And I think that's our final answer, assuming I didn't make any boo boos along the way.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0wait which is the mx and b?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0oh it is correct….

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\bf y=\color{royalblue}{(234e^{27}6)}x \color{orangered}{689e^{27}}\]\[\large\bf y=\color{royalblue}{m}x +\color{orangered}{b}\]
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