Find the number of sides of each of the two polygons if the total numbers of sides of the polygon is 15, and the sum of the number of diagonals is 36.

- anonymous

- katieb

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- anonymous

the number of sides is 30

- anonymous

i was able to get the number of sides but i don't know how to show the solution

- anonymous

the number of side is 9 and 6
i just need a solution how to get this

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## More answers

- anonymous

then the numbers of sides of the polygon should be polygons

- kc_kennylau

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- kc_kennylau

http://www.dummies.com/how-to/content/how-to-find-the-number-of-diagonals-in-a-polygon.html

- kc_kennylau

So the number of diagonals of a polygon with \(n\) sides is \(\dfrac{n(n-3)}2\)

- kc_kennylau

Why don't you set up equations :)

- anonymous

number of diagonals i already given. i need a solution.

- anonymous

can you help me?

- kc_kennylau

You could try letting the numbers of sides of the two polygons be \(m\) and \(n\) respectively :)

- anonymous

can you pls show me the solution. i got this m(m-3)/2 + n(n-3)/2 = 36

- kc_kennylau

Ok I'll set up the equations for you but you'll work out the steps yourself :)
\[m+n=15\]\[\frac{m(m+3)}2+\frac{n(n+3)}2=36\]

- kc_kennylau

ok here's a hint: \(m=15-n\)

- anonymous

m^2-3m+n^2-3n = 72
m^2+n^2-3(m+n) = 72
we know that m+n = 15
m^2+n^2-3(15) = 72
m^2+n^2 = 27
after that i dont know

- anonymous

substitute 15-n for m

- anonymous

huh?

- kc_kennylau

substitute \(m=15-n\) to \(\dfrac{m(m-3)}2+\dfrac{n(n-3)}2=36\) :)

- kc_kennylau

into*

- anonymous

\[\left( 15-n ^{} \right)^{2}-3\left( 15-n \right)+n ^{2}-3n=72\]

- kc_kennylau

yep, and this will be a quadratic :)

- anonymous

im stuck

- anonymous

i got -108 = -27n+n^2

- kc_kennylau

Have you learnt quadratic? :)

- kc_kennylau

Use quadratics pl0x

- anonymous

can you just pls provide me the whole solution
im stuck. sorry if im stupid about this..

- anonymous

i stop studying for 5years and i need to recall everything about geometry

- anonymous

2n^2-30n+108=0

- anonymous

(_n+_)(_n-_) factor

- anonymous

you did it right you just got 27 instead of 30

- anonymous

how did you get the 30?

- anonymous

got it

- anonymous

from the first equation
225-30n+n^2-45+3n+n^2-3n=72

- anonymous

combine like terms

- anonymous

after that. what is next?

- anonymous

(15-n)^2 gave me the thirty

- anonymous

how do i get the n now?

- anonymous

then you factor the 2n^2-30n+108
you can divide both sides by two to make it easier
n^2-15n+54

- anonymous

two factors of 54 that total to -15

- anonymous

(x-_)*(x-_)=0

- anonymous

(n-9)(n-6)

- anonymous

yes
so those are your sides

- anonymous

thank you so much for your patience with me. i really appreciate it.

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