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wendylisette

  • one year ago

how do you type the infinity sign on a graphing calculator ?

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  1. amistre64
    • one year ago
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    1E99

  2. wendylisette
    • one year ago
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    i just write it out ?

  3. wendylisette
    • one year ago
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    it says error

  4. amistre64
    • one year ago
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    thats calculator for: 1x10^(99)

  5. Decart
    • one year ago
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    which model

  6. wendylisette
    • one year ago
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    TI - 84 plus

  7. amistre64
    • one year ago
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    your comma button has an EE atop it, shift to get it

  8. wendylisette
    • one year ago
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    oh i see it now , hold up

  9. austinL
    • one year ago
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    Do you have a TI-89? These bad boys have an infinity BUTTON!! :D

  10. wendylisette
    • one year ago
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    oh no i have a 84 /:

  11. hihi67
    • one year ago
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    lol @austinL

  12. amistre64
    • one year ago
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    ti84 is the most ill go ... after that they started having to have terabytes for the instruction manuals and i gave up :)

  13. wendylisette
    • one year ago
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    @amistre64 it says EE but you said it was IE99

  14. austinL
    • one year ago
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    Same thing :)

  15. amistre64
    • one year ago
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    it not my fault they cant type lol

  16. austinL
    • one year ago
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    Button likely says EE, but on screen it should say E

  17. wendylisette
    • one year ago
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    ok lemme try

  18. amistre64
    • one year ago
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    the output on the screen is still: one: 1 2nd, , : E 99: 99

  19. wendylisette
    • one year ago
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    is it a one or an I ?

  20. amistre64
    • one year ago
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    they might have done that to distinguish it fromthe alpha E key :/

  21. amistre64
    • one year ago
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    an i is not a real numerical value

  22. austinL
    • one year ago
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    "Imaginary"

  23. amistre64
    • one year ago
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    i^k is one of 4 values ... why are you needing an infinity?

  24. wendylisette
    • one year ago
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    Find the sum of the infinite geometric series, if possible. Show steps, if possible. \sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j-1}

  25. wendylisette
    • one year ago
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    hold up

  26. wendylisette
    • one year ago
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    \[\sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j-1}\]

  27. amistre64
    • one year ago
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    \[\sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j-1}\] \[\sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j}~.5^{-1}\] \[\frac{4}{.5}\sum_{{j}={1}}^{\infty}0.5^{j}\]

  28. wendylisette
    • one year ago
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    aha now what ? lol

  29. amistre64
    • one year ago
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    is .5 less than 1?

  30. amistre64
    • one year ago
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    theres a formula for this ....

  31. wendylisette
    • one year ago
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    yes

  32. wendylisette
    • one year ago
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    whats the formula ? im sorry my teacher doesnt give me all this info /:

  33. amistre64
    • one year ago
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    \[\frac{1-r^k}{1-r}\] if r < 1, then the limit as k to infinity is \[\frac{1}{1-r}\]

  34. wendylisette
    • one year ago
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    whats r though ? the common ratio ?

  35. wendylisette
    • one year ago
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    but would it be possible to find the sum ?

  36. amistre64
    • one year ago
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    let me rechk my thought tho ... S = r + r^2 + r^3 + ... + r^n -rS = - r^2 - r^3 - ... - r^n - r^(n+1) ----------------------------------- (1-r)S = r + 0 ..........................- r^(n+1) S= r - r^(n+1) ----------- 1 - r

  37. amistre64
    • one year ago
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    if r < 1 then that exponented part goes to 0 leaving us: S = r/(1-r) for the sum

  38. amistre64
    • one year ago
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    might be better stated the |r| < 1, but why nitpick

  39. amistre64
    • one year ago
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    \[\frac{4}{.5}\sum_{{j}={1}}^{\infty}0.5^{j}\] \[\frac{4}{.5}~\frac{.5}{1-.5}\] \[\frac{4}{.5}=8\]

  40. amistre64
    • one year ago
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    http://www.wolframalpha.com/input/?i=sum+4%28.5%29%5E%28n-1%29%2C+n%3D1+to+inf

  41. wendylisette
    • one year ago
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    thanks soooo much !

  42. amistre64
    • one year ago
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    youre welcome, as far as i know the ti84 does not have an infinite sum function

  43. wendylisette
    • one year ago
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    yes im aware haha

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