wendylisette
how do you type the infinity sign on a graphing calculator ?



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amistre64
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1E99

wendylisette
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i just write it out ?

wendylisette
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it says error

amistre64
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thats calculator for: 1x10^(99)

Decart
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which model

wendylisette
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TI  84 plus

amistre64
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your comma button has an EE atop it, shift to get it

wendylisette
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oh i see it now , hold up

austinL
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Do you have a TI89? These bad boys have an infinity BUTTON!! :D

wendylisette
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oh no i have a 84 /:

hihi67
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lol @austinL

amistre64
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ti84 is the most ill go ... after that they started having to have terabytes for the instruction manuals and i gave up :)

wendylisette
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@amistre64 it says EE but you said it was IE99

austinL
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Same thing :)

amistre64
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it not my fault they cant type lol

austinL
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Button likely says EE, but on screen it should say E

wendylisette
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ok lemme try

amistre64
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the output on the screen is still:
one: 1
2nd, , : E
99: 99

wendylisette
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is it a one or an I ?

amistre64
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they might have done that to distinguish it fromthe alpha E key :/

amistre64
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an i is not a real numerical value

austinL
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"Imaginary"

amistre64
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i^k is one of 4 values ...
why are you needing an infinity?

wendylisette
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Find the sum of the infinite geometric series, if possible. Show steps, if possible.
\sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j1}

wendylisette
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hold up

wendylisette
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\[\sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j1}\]

amistre64
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\[\sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j1}\]
\[\sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j}~.5^{1}\]
\[\frac{4}{.5}\sum_{{j}={1}}^{\infty}0.5^{j}\]

wendylisette
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aha now what ? lol

amistre64
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is .5 less than 1?

amistre64
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theres a formula for this ....

wendylisette
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yes

wendylisette
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whats the formula ? im sorry my teacher doesnt give me all this info /:

amistre64
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\[\frac{1r^k}{1r}\]
if r < 1, then the limit as k to infinity is
\[\frac{1}{1r}\]

wendylisette
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whats r though ? the common ratio ?

wendylisette
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but would it be possible to find the sum ?

amistre64
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let me rechk my thought tho ...
S = r + r^2 + r^3 + ... + r^n
rS =  r^2  r^3  ...  r^n  r^(n+1)

(1r)S = r + 0 .......................... r^(n+1)
S= r  r^(n+1)

1  r

amistre64
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if r < 1 then that exponented part goes to 0 leaving us:
S = r/(1r) for the sum

amistre64
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might be better stated the r < 1, but why nitpick

amistre64
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\[\frac{4}{.5}\sum_{{j}={1}}^{\infty}0.5^{j}\]
\[\frac{4}{.5}~\frac{.5}{1.5}\]
\[\frac{4}{.5}=8\]


wendylisette
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thanks soooo much !

amistre64
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youre welcome, as far as i know the ti84 does not have an infinite sum function

wendylisette
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yes im aware haha