anonymous
  • anonymous
how do you type the infinity sign on a graphing calculator ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
1E99
anonymous
  • anonymous
i just write it out ?
anonymous
  • anonymous
it says error

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More answers

amistre64
  • amistre64
thats calculator for: 1x10^(99)
anonymous
  • anonymous
which model
anonymous
  • anonymous
TI - 84 plus
amistre64
  • amistre64
your comma button has an EE atop it, shift to get it
anonymous
  • anonymous
oh i see it now , hold up
austinL
  • austinL
Do you have a TI-89? These bad boys have an infinity BUTTON!! :D
anonymous
  • anonymous
oh no i have a 84 /:
hihi67
  • hihi67
lol @austinL
amistre64
  • amistre64
ti84 is the most ill go ... after that they started having to have terabytes for the instruction manuals and i gave up :)
anonymous
  • anonymous
@amistre64 it says EE but you said it was IE99
austinL
  • austinL
Same thing :)
amistre64
  • amistre64
it not my fault they cant type lol
austinL
  • austinL
Button likely says EE, but on screen it should say E
anonymous
  • anonymous
ok lemme try
amistre64
  • amistre64
the output on the screen is still: one: 1 2nd, , : E 99: 99
anonymous
  • anonymous
is it a one or an I ?
amistre64
  • amistre64
they might have done that to distinguish it fromthe alpha E key :/
amistre64
  • amistre64
an i is not a real numerical value
austinL
  • austinL
"Imaginary"
amistre64
  • amistre64
i^k is one of 4 values ... why are you needing an infinity?
anonymous
  • anonymous
Find the sum of the infinite geometric series, if possible. Show steps, if possible. \sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j-1}
anonymous
  • anonymous
hold up
anonymous
  • anonymous
\[\sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j-1}\]
amistre64
  • amistre64
\[\sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j-1}\] \[\sum_{{j}={1}}^{\infty}4 \cdot 0.5^{j}~.5^{-1}\] \[\frac{4}{.5}\sum_{{j}={1}}^{\infty}0.5^{j}\]
anonymous
  • anonymous
aha now what ? lol
amistre64
  • amistre64
is .5 less than 1?
amistre64
  • amistre64
theres a formula for this ....
anonymous
  • anonymous
yes
anonymous
  • anonymous
whats the formula ? im sorry my teacher doesnt give me all this info /:
amistre64
  • amistre64
\[\frac{1-r^k}{1-r}\] if r < 1, then the limit as k to infinity is \[\frac{1}{1-r}\]
anonymous
  • anonymous
whats r though ? the common ratio ?
anonymous
  • anonymous
but would it be possible to find the sum ?
amistre64
  • amistre64
let me rechk my thought tho ... S = r + r^2 + r^3 + ... + r^n -rS = - r^2 - r^3 - ... - r^n - r^(n+1) ----------------------------------- (1-r)S = r + 0 ..........................- r^(n+1) S= r - r^(n+1) ----------- 1 - r
amistre64
  • amistre64
if r < 1 then that exponented part goes to 0 leaving us: S = r/(1-r) for the sum
amistre64
  • amistre64
might be better stated the |r| < 1, but why nitpick
amistre64
  • amistre64
\[\frac{4}{.5}\sum_{{j}={1}}^{\infty}0.5^{j}\] \[\frac{4}{.5}~\frac{.5}{1-.5}\] \[\frac{4}{.5}=8\]
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=sum+4%28.5%29%5E%28n-1%29%2C+n%3D1+to+inf
anonymous
  • anonymous
thanks soooo much !
amistre64
  • amistre64
youre welcome, as far as i know the ti84 does not have an infinite sum function
anonymous
  • anonymous
yes im aware haha

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