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Wow that is pretty hard :/
Do you have a teacher to contact or ask?

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Other answers:

Yes but I was told that I was "already taught" the information , when I wasn't ..
oh, i really hate when that happens...
I take notes on my school work, it really helps me out.
i can try to search it. would that help you out?
It might lol . And i do my schooling online btw
oh okay i do to... :)
Lol okayy .
if u solve the equation u have, by squaring \[\large \sqrt{4x-6}=\sqrt{x} \] \[\large 4x-6=x\] \[\large 3x=6 \] \[\large x=2 \] right?
Correct !
now, if u replace x=2 into the original equation, does it actually solve the equation?
i.e., is it a valid solution?
Yes :o
so, is it extraneous or non-extraneous?
i.e., it is non-valid (extraneous) or valid (non-extraneous)? http://en.wikipedia.org/wiki/Extraneous_and_missing_solutions
non-extraneous of course haha
I tried and tried........got no clue!!!!!!!!!!!!!!! :(
it's okay ! lol
Lol
u got it?
@helder_edwin , yess !
good. glad to help
i'm glad you did !

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