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anonymous
 2 years ago
Choose the equation of the line passing through the point (1, 3) and perpendicular to y = negative one thirdx + 7.
y = 3x  12
y = 3x + 6
y = 3x  6
y = 3x
anonymous
 2 years ago
Choose the equation of the line passing through the point (1, 3) and perpendicular to y = negative one thirdx + 7. y = 3x  12 y = 3x + 6 y = 3x  6 y = 3x

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0first we need to find the slope of the equation given. y = 1/3x + 7 (In y = mx + b form, the m is the slope. Therefore, the slope of this line is 1/3) But we need a perpendicular line, so we need the negative reciprocal of that slope. All that means is " flip " the slope and change the sign. The negative reciprocal of 1/3 = 3/1 or just 3 (you see how I flipped the slope and changed the sign) so we have slope(m) = 3 (1,3) x = 1 and y = 3 y = mx + b and solve for b 3 = 3(1) + b 3 = 3 + b 3 + 3 = b 6 = b your perpendicular line is : y = 3x + 6

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you so much. will you help on another ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0hoose the equation of the line passing through the point (3, 1) and parallel to y = x  4. y = x + 2 y = x  2 y = x + 4 y = x  4

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0y = x  4 (slope is 1) Since we need a parallel slope, the original slope stays the same. slope(m) = 1 (3,1) x = 3 and y = 1 y = mx + b for b 1 = 1(3) + b 1 = 3 + b 1  3 = b 2 = b your parallel line is : y = x  2

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Since you worked it out I understand now.. Thanks you (:
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