Tn = 7n^2 - n^3 T1 = 7(1)^2 - (1)^3 = 6 T2 = 7(2)^2 - (2)^3 = 20 .... ... T6 = 7(6)^2 - (6)^3 = 78 T7 = 7(7)^2 - (7)^3 = 0 so, it is T6 = 78
i know this is also a answer but i need answer which is in options?
how did u get Tn RadEn ?
yeah, i know how to find Tn, but i wanted to know whether RadEn used any different/simpler method....
his method is wrong.
he got the answer which is in the choices, how u say its wrong ?
because if we put n=6,the answer comes to be is 36 but in actual(followed by series)the answer would be 50
isiliye mujhe lagta h ki voh galat h
" in actual(followed by series)the answer would be 50" what does this even mean ?
iska matla agar hum uske tarike se follow karien to iska answer 50 aana chaihye series ke hisaab se lekin actual main 36 aa raha h..... iska method thode se hi digits ke liye apply hota h
lol, i could translate that in hindi myself too
why u say answer should be 50 ?
bhaiya , yeh question ntse 2013 RAJ. main poocha gaya tha aur FIITJEE vaalein bata rahein h ki iska answer DATA INADEQUATE h aur CAREER POINT vallein bata rahein h ki iska answer 36 h
to iska kya answer hoga bhaiya?
the answer to this is indeed 36 as shown corretly by RadEn
i just wanted to know any simpler way of finding Tn :P
yeah...this logic doesn't apply in NTSE STAGE 1
i think there is another logic simpler logic for this
i think it does apply, the third differences are constant
so, x - 52 - (-10) = -6
x= 42 - 6 = 36
oh lol but i guess they can't use wolf.... so using the 3rd difference is a simpler manual way...
yeah, just input some numbers in wolfram :)
and nobody can see notifications its the bug OS admins are trying to fix