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Lena772
Group Title
(a) find an equation of the tangent line to
the graph of at the given point, (b) use a graphing utility to graph the function and its tangent line at the point, and (c) use the derivative feature of the graphing utility to confirm your
results.
 one year ago
 one year ago
Lena772 Group Title
(a) find an equation of the tangent line to the graph of at the given point, (b) use a graphing utility to graph the function and its tangent line at the point, and (c) use the derivative feature of the graphing utility to confirm your results.
 one year ago
 one year ago

This Question is Closed

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
function: y= cos 3x point: (pi/4, sqrt2/2)
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
where wer u stuck ?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
i saw u doing a similar problem the other day ? :)
 one year ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
take the derivative
 one year ago

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
I just get confused when trig is added in
 one year ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
do you know what the derivative is
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
so, slope = m = dy/dx = 3sin3x
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
since u want the slope at point: (pi/4, sqrt2/2) evaluate slope at x = pi/4
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dy/dx at x = pi/4 : 3sin(3*pi/4) = ?
 one year ago

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
@ganeshie8
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
that doesnt look right you should get : dy/dx at x = pi/4 : 3sin(3*pi/4) = \(\large \frac{3}{\sqrt{2}}\)
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
now that u knw slope, m = \(\large \frac{3}{\sqrt{2}}\) point: (pi/4, sqrt2/2) wats the equation of tangent in point slope form ?
 one year ago

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
y(sqrt2/3)=(3/sqrt2)(x(pi/4)
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
thats right !
 one year ago

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
So that's for a? What would the graph look like for b? Do I just put that equation into Geogebra?
 one year ago

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
@ganeshie8
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
yup graph all 3 below : 1) function: y= cos 3x 2) point: (pi/4, sqrt2/2) 3) tangent : y(sqrt2/\(\color{red}{2}\))=(3/sqrt2)(x(pi/4)
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
u should get exactly like the one attached
 one year ago
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