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Lena772
Group Title
(a) find an equation of the tangent line to
the graph of at the given point, (b) use a graphing utility to graph the function and its tangent line at the point, and (c) use the derivative feature of the graphing utility to confirm your
results.
 8 months ago
 8 months ago
Lena772 Group Title
(a) find an equation of the tangent line to the graph of at the given point, (b) use a graphing utility to graph the function and its tangent line at the point, and (c) use the derivative feature of the graphing utility to confirm your results.
 8 months ago
 8 months ago

This Question is Closed

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
function: y= cos 3x point: (pi/4, sqrt2/2)
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
where wer u stuck ?
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
i saw u doing a similar problem the other day ? :)
 8 months ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
take the derivative
 8 months ago

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
I just get confused when trig is added in
 8 months ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
do you know what the derivative is
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
so, slope = m = dy/dx = 3sin3x
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
since u want the slope at point: (pi/4, sqrt2/2) evaluate slope at x = pi/4
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dy/dx at x = pi/4 : 3sin(3*pi/4) = ?
 8 months ago

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
@ganeshie8
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
that doesnt look right you should get : dy/dx at x = pi/4 : 3sin(3*pi/4) = \(\large \frac{3}{\sqrt{2}}\)
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
now that u knw slope, m = \(\large \frac{3}{\sqrt{2}}\) point: (pi/4, sqrt2/2) wats the equation of tangent in point slope form ?
 8 months ago

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
y(sqrt2/3)=(3/sqrt2)(x(pi/4)
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
thats right !
 8 months ago

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
So that's for a? What would the graph look like for b? Do I just put that equation into Geogebra?
 8 months ago

Lena772 Group TitleBest ResponseYou've already chosen the best response.1
@ganeshie8
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
yup graph all 3 below : 1) function: y= cos 3x 2) point: (pi/4, sqrt2/2) 3) tangent : y(sqrt2/\(\color{red}{2}\))=(3/sqrt2)(x(pi/4)
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
u should get exactly like the one attached
 8 months ago
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