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well what do you know about those 2 functions in relation to each other

or maybe call it reciprocal? im not good at my language

As far as I know it's reciprocal is csc=1/sin

alright then. what do you think the answer is

something like -1/2.

I just have different ones like tanθ if cotθ=sqrt6/2 and I don't really understand

so your correct on this problem. do you know about radians yet for the other problems?

WHat do you mean radians?

and cot and tan are reciprocals as well. radians-degrees. have you now done the unit circle yet?

I don't recall so I am going to have to say no.

Yea, so how would I go on in doing that? I am in Pre-cal if that makes a difference.

tell me where you are at on the second problem

hm. what is the reciprocal of
\[\frac{ \sqrt{6} }{ 2 }\]

Umm tbh I'm not really sure :/

Oh ok I see so now I have to get the reciprocal.

but it would be 6/2sqrt2

oh I see now, so then the answer is 2/√6, I don't have to rationalize anything I believe.

keeping in mind
\[\sqrt{6}*\sqrt{6}=\sqrt{36}\]

Ok, thanks a lot! really appreciate the help!

see how I multiplied the top and bottom by
\[\sqrt{6}\]

so 2*sqrt6/6

looks like you can simplify it a little more think of it as
\[\frac{ 2 }{ 6 }*\sqrt{6}\]