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jacalneaila
 one year ago
the perimeter of a rectangle is 256 cm. if the sides are in the ratio 2:5. find the rectangle?.. with medal
jacalneaila
 one year ago
the perimeter of a rectangle is 256 cm. if the sides are in the ratio 2:5. find the rectangle?.. with medal

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ranga
 one year ago
Best ResponseYou've already chosen the best response.1Let L be the length and W be the width of the rectangle. Perimeter = 2(L+W) = 256 divide both sides by 2 L + W = 128  (1) Sides are in the ratio 2:5 That means W/L = 2/5 cross multiply 5W = 2L divide both sides by 5 W = 2L/5  (2) Put W from equation (2) into (1) and solve for L. Then put the L value in (2) and solve for W.

jacalneaila
 one year ago
Best ResponseYou've already chosen the best response.0can you explain it clearly

ranga
 one year ago
Best ResponseYou've already chosen the best response.1Do you want to know how to solve or do you want to know how I got the 2 equations?

jacalneaila
 one year ago
Best ResponseYou've already chosen the best response.0i want to know how to solve

ranga
 one year ago
Best ResponseYou've already chosen the best response.1L + W = 128  (1) W = 2L/5  (2) Put W = 2L/5 in the first equation L + 2L/5 = 128 multiply each term by 5 to get rid of the fraction: 5L + 2L = 640 7L = 640 L = 640/7 = 91.43 cm Put this in (2) W = 2L/5 = 2*91.43/5 = 36.57 cm. L = 91.43 cm; W = 36.57 cm.
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