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jacalneaila
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the perimeter of a rectangle is 256 cm. if the sides are in the ratio 2:5. find the rectangle?.. with medal
 11 months ago
 11 months ago
jacalneaila Group Title
the perimeter of a rectangle is 256 cm. if the sides are in the ratio 2:5. find the rectangle?.. with medal
 11 months ago
 11 months ago

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ranga Group TitleBest ResponseYou've already chosen the best response.1
Let L be the length and W be the width of the rectangle. Perimeter = 2(L+W) = 256 divide both sides by 2 L + W = 128  (1) Sides are in the ratio 2:5 That means W/L = 2/5 cross multiply 5W = 2L divide both sides by 5 W = 2L/5  (2) Put W from equation (2) into (1) and solve for L. Then put the L value in (2) and solve for W.
 11 months ago

jacalneaila Group TitleBest ResponseYou've already chosen the best response.0
@ranga what??
 11 months ago

jacalneaila Group TitleBest ResponseYou've already chosen the best response.0
can you explain it clearly
 11 months ago

ranga Group TitleBest ResponseYou've already chosen the best response.1
Do you want to know how to solve or do you want to know how I got the 2 equations?
 11 months ago

jacalneaila Group TitleBest ResponseYou've already chosen the best response.0
i want to know how to solve
 11 months ago

ranga Group TitleBest ResponseYou've already chosen the best response.1
L + W = 128  (1) W = 2L/5  (2) Put W = 2L/5 in the first equation L + 2L/5 = 128 multiply each term by 5 to get rid of the fraction: 5L + 2L = 640 7L = 640 L = 640/7 = 91.43 cm Put this in (2) W = 2L/5 = 2*91.43/5 = 36.57 cm. L = 91.43 cm; W = 36.57 cm.
 11 months ago
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