hkmiu
  • hkmiu
cos(arctan(sqrt3/7))?? http://media.education2020.com/evresources/649-07-06-00-00_files/i0200000.jpg
Mathematics
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hkmiu
  • hkmiu
cos(arctan(sqrt3/7))?? http://media.education2020.com/evresources/649-07-06-00-00_files/i0200000.jpg
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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hkmiu
  • hkmiu
\[\cos(\arctan (\frac{ \sqrt{3} }{ 7 })) \]
myininaya
  • myininaya
Let the inside be called a. arctan(sqrt(3)/7)=a then use the fact that tan is the inverse of arctan to rewrite that as tan(a)=sqrt(3)/7 Draw a right triangle and put these measurements in their proper place. You should see that one measurement for one leg is missing. You can use the Pythagorean thm for that. Then find cos(a) and that is your answer.
hkmiu
  • hkmiu
Oh okay, thank you !!! :D

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myininaya
  • myininaya
Ok. Well if you have anymore questions here on this problem don't be afraid to ask.

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