Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

cookiesandmilk

  • 2 years ago

Simplify: x^-1/7*x^-1/6

  • This Question is Closed
  1. alffer1
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    When you have the same base, you can just add the exponents. To add these ones, you need to put them over a common denominator.

  2. cookiesandmilk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay did that :)

  3. jdoe0001
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \(\bf \Large x^{-\frac{1}{7}}\cdot x^{-\frac{1}{6}}\implies x^{-\frac{1}{7}+-\frac{1}{6}\implies \frac{?}{LCD?}}\)

  4. cookiesandmilk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay, I think the answer is

  5. cookiesandmilk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Is that correct? (:

  6. jdoe0001
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeap

  7. cookiesandmilk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Awesome thanks! :) :)

  8. alffer1
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yup is right

  9. cookiesandmilk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks for the help peoples!

  10. jdoe0001
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \(\bf \Large {x^{-\frac{1}{7}}\cdot x^{-\frac{1}{6}}\implies x^{-\frac{1}{7}+-\frac{1}{6}\implies \frac{-13}{42}}\implies \cfrac{1}{x^{\frac{13}{42}}}}\)

  11. jdoe0001
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yw

  12. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy