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sta880
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f(x)=x^3+4x^25x+6, I need to find the remainder when f(x) is divided by (x2). How can I do that?
 10 months ago
 10 months ago
sta880 Group Title
f(x)=x^3+4x^25x+6, I need to find the remainder when f(x) is divided by (x2). How can I do that?
 10 months ago
 10 months ago

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mathmale Group TitleBest ResponseYou've already chosen the best response.0
You could actually do the division (long division). Or you could use synthetic division: from the divisor (x2) we'd get divisor 2; from the function f(x), we'd get the coefficients 1, 4, 5 and 6. This synthetic division problem then becomes: 2  1 4 5 6 _______2__12_14_____ 1 6 7 20 and 20 is the remainder. I have little idea of where you're coming from, so why not indicate whether you'd prefer to do this problem using long division or using synthetic division; perhaps then I can guide you through more of either procedure.
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
Or much easier way... Plug 2 in the place of in your f expression
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
we can write f/(x2) as f(x)/(x2)=Q(x)+R/(x2) or f(x)=Q(x)*(x2)+R f(2)=Q(2)*(22)+R f(2)=Q(2)*(0)+R f(2)=0+R f(2)=R R represents remainder Q represents quotient
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
This is called the remainder theorem
 10 months ago

mathmale Group TitleBest ResponseYou've already chosen the best response.0
Cool, myininaya!
 10 months ago
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