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sta880
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f(x)=x^3+4x^25x+6, I need to find the remainder when f(x) is divided by (x2). How can I do that?
 8 months ago
 8 months ago
sta880 Group Title
f(x)=x^3+4x^25x+6, I need to find the remainder when f(x) is divided by (x2). How can I do that?
 8 months ago
 8 months ago

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mathmale Group TitleBest ResponseYou've already chosen the best response.0
You could actually do the division (long division). Or you could use synthetic division: from the divisor (x2) we'd get divisor 2; from the function f(x), we'd get the coefficients 1, 4, 5 and 6. This synthetic division problem then becomes: 2  1 4 5 6 _______2__12_14_____ 1 6 7 20 and 20 is the remainder. I have little idea of where you're coming from, so why not indicate whether you'd prefer to do this problem using long division or using synthetic division; perhaps then I can guide you through more of either procedure.
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
Or much easier way... Plug 2 in the place of in your f expression
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
we can write f/(x2) as f(x)/(x2)=Q(x)+R/(x2) or f(x)=Q(x)*(x2)+R f(2)=Q(2)*(22)+R f(2)=Q(2)*(0)+R f(2)=0+R f(2)=R R represents remainder Q represents quotient
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
This is called the remainder theorem
 8 months ago

mathmale Group TitleBest ResponseYou've already chosen the best response.0
Cool, myininaya!
 8 months ago
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