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Your try to solve for x?
hey after this, can u go back to ur previous question, ive replied to ur question
It says to factor each polynomial
First set it equal to 0 : \[6x^2(4x^2+3) = 0\] Divide both sides by 6: \[x^2(4x^2+3) = 0\] Split into two equations: \[x^2 = 0 or 4x^2 + 3 = 0\] x = 0 or 4x^2 = -3 Divide both sides by 4: x = 0 or x^2 = -3/4
So would I just answer it like that on my homework? and could u help me with some other questions please?
Because x^2 = -3/4 has no solution since for all x on the real line, x^2 >= 0 and -3/4 < 0: x = 0 is the anser
Well, are you looking for Real roots or Complex roots?
i dont know it just tells me to factor each polynomial
Your sure the problem is written correctly?
oh it says factor each product
i ment simplify each product it says
can u help me with 16b^4+8b^2+20b it says factor each polnomial
For the second one you could factor out 4b resulting in: \[4b(4b^3 + 2b + 5)\]
ok so that be the answer?
I can't see any other way to simplify it, but I'm not the best at this sort of thing
I have to go work on some school now though :/
ohh i still need help im soo behind
does this look right (x+2)(x+9) X^2+11x+18 ¼(2x+11)^2- 49/4 X(x+11)+18 ?