x+y=-7 2x-y=-8

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I'm guessing you want to solve the system.
To do so just add the equations. \[\huge \left(\begin{matrix} x+y = -7 \\ 2x-y=-8\end{matrix}\right)\]
What do you get?

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Other answers:

you would get 2x=-15 i think cuz you cross out either the x or y
i cross out the y
x+y=-7 2x-y=-8 ---------- 3x - 0 = -15 i though it was supposed to be 3x = -15 also, simplify it by dividing both sides by 3 and you get x = -5
Correct, you cross out the y but you forgot to add the x. you get as twilight mentioned 3x = -15 from there you divide by 3 to both sides to get your x value of -5.
x + y = -7 -5 + y = -7 y = -2
(-5,-2) is your solution set to your system.

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